Given: <span>2x-y-3=0.
find </span>equation for the line perpendicular to the given line that goes through the given point:<span>
(2;-1)koord of direction vector (i`m not know how it is called at you, because i'm from russia)</span><span>
=> (x-0)/2=(y-4)/-1 (</span>canonical <span>equation)
=>x+2y-8=0(general </span><span>equation)
</span>
<span>further:
{x+2y-8=0
{2x-y-3 =0 => y=13/5 x=14/5
(14/5; 13/5) - koord point on line
</span>|dist|=sqrt( (14/5-0)^2 + (13/5-4)^2 ) = sqtr(7.72) = 2.78
Удачи!
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The answer is 19 I subtracted the 2 biggest numbers
The maximum area of a rectangle when given perimeter is simply perimeter/sides.
To get the maximum area, simply divide 160 (perimeter) by 4 (sides in a rectangle) and then square the result:
160/4 = 40
40 x 40 = 1600
The maximum area, when the sides are all of the same length, is <u><em>1600 square yards.
</em></u><em></em>Hope this helps!
<em>~ArchimedesEleven</em><u><em>
</em></u>
Answer:229.1
Step-by-step explanation: to much work I thought to hard that’s the answer your welcome buddy
