14.86 is the answer to this question
Answer:
Therefore the concentration of salt in the incoming brine is 1.73 g/L.
Step-by-step explanation:
Here the amount of incoming and outgoing of water are equal. Then the amount of water in the tank remain same = 10 liters.
Let the concentration of salt be a gram/L
Let the amount salt in the tank at any time t be Q(t).

Incoming rate = (a g/L)×(1 L/min)
=a g/min
The concentration of salt in the tank at any time t is =
g/L
Outgoing rate =



Integrating both sides

[ where c arbitrary constant]
Initial condition when t= 20 , Q(t)= 15 gram


Therefore ,
.......(1)
In the starting time t=0 and Q(t)=0
Putting t=0 and Q(t)=0 in equation (1) we get









Therefore the concentration of salt in the incoming brine is 1.73 g/L
60% if there are only 10 white and black balls
Answer:
I think this will help
Step-by-step explanation:
Make a point at(-5,-6) then go up two boxes and right three boxes.
Answer:
35% discount.
Step-by-step explanation:
28.60 / 44 = 13/20
13/20 = 65/100 = 65%
28.60 is 65% of 44
100 - 65 = 35
Therefore, the discount is 35%.