Answer: The answer is 314.28 cm² (approx.).
Step-by-step explanation: Given that an engineer is going to install a new water pipe. The diameter of this circular pipe is, d = 20 cm.
We need to find the area 'A' of the circular cross-section of the pipe.
Given, diameter of the circular section is
So, the radius of the circular cross-section will be
Therefore, cross-sectional area of the pipe is
Thus, the answer is 314.28 cm² (approx.).
Answer:
3x^2 + 9x + 1
Or
3x ( x + 3 ) + 1
Step-by-step explanation:
(5x - 2 +3x^2 ) + (4x + 3 )
To make this a little bit more easier to read, you can remove the parentheses:
5x - 2 + 3x^2 + 4x + 3
Now, write in a way so that the like terms are next to each other:
3x^2 + 5x + 4x - 2 + 3
Now simplify the 'x' terms to get:
3x^2 + 9x - 2 + 3
Now, simplify the integers (the ones with now variables with them) to get:
3x^2 + 9x + 1
If you want, you can factor out the 3x for two of the terms to get :
3x ( x + 3 ) + 1
Therefore, your simplest form can either be 3x^2 + 9x + 1 OR 3x (x + 3 ) + 1
Answer:
it is c it is c it is c it is c
7x/x-4 * x/x+7
mutiply the numerators together
(7x)(x)= 7x^ 2
mutiply the denominators together
(x-4)(x+7)
(x)(x)(7)(x)= x^2+7x
(-4)(x)(-4)(7)= -4x-28
x^2+7x-4x-28
x^2+3x-28
Answer:
7x^2/x^ 2+3x-28
The average rate of change is m=5.
Hope this helped.
