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Elza [17]
2 years ago
7

WILL MARK BRAINLIST PLS ANSWER ITS VERY IMPORTANT ​

Mathematics
1 answer:
Mrac [35]2 years ago
3 0

Answer:

Step-by-step explanation:

a) 4th

b) 300

c) 2nd and 5th

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Jeff and his cousin work during the summer for a roofing company. Jeff's cousin has been working
sdas [7]

Answer:

1

Step-by-step explanation:

doesn't work hard enough

3 0
3 years ago
Read 2 more answers
Write in a number in which the value of the 8 is ten times greater than the value of the 8 in 8304?
Serhud [2]

Thee number in which case has the value of the 8 ten times greater than than the value of the 8 in 8304 as required in the task content is; 83450.

<h3>Which number has the value of the 8 is ten times greater than the value of the 8 in 8304?</h3>

It follows from the task content that the number which satisfies the condition that, the value of its 8 is ten times greater than the value of the 8 in 8304 is to be determined.

It follows from place value that the 8 in 8304 has a value of; 8 × 1000 = 8000.

Hence, an example of a number that is ten times greater is; 10 × 80,000.

Ultimately, an example of the required number as in the task content is; 83450 where it's 8 digit is ten times greater than that in 8304.

Read more on place value;

brainly.com/question/569339

#SPJ1

6 0
1 year ago
Alguien puede ayudarme en esto
Montano1993 [528]
Lo siento, español no es mi primer lengua, pero trataré ayudar. ¿Qué significa L1, L2, y L3? No recuerdo.
Necesita multiplicar
x-3 • x+2
x-2 • x-1
Pero, obtendrías esto, y no ayudaría
x^2-6 = x^2+2
Es imposible resolver para x con eso.
Creo que la respuesta es e. no existe tal valor para x

7 0
3 years ago
Complete the recursive formula of the arithmetic sequence 4, 22, 40,58, ....
dlinn [17]

Answer:

b (1)= 4

b (n)= b (n-1)+ 18

Step-by-step explanation:

5 0
3 years ago
Write as a product: 25a2−0.01b10
Yakvenalex [24]

Answer:

We conclude that:

25a^2-0.01b^{10}=\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)

Step-by-step explanation:

Given the expression

25a^2-0.01b^{10}

Rewrite 25a^2-0.01b^{10} as \left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2

so

25a^2-0.01b^{10}=\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2

Apply difference of two squares formulas:

x^2-y^2=\left(x+y\right)\left(x-y\right)

so

\left(5a\right)^2-\left(\sqrt{0.01}b^5\right)^2=\left(5a+\sqrt{0.01}b^5\right)\left(5a-\sqrt{0.01}b^5\right)

                               =\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)    ∵ \sqrt{0.01}=0.1,

Therefore, we conclude that:

25a^2-0.01b^{10}=\left(5a+0.1b^5\right)\left(5a-0.1b^5\right)

7 0
2 years ago
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