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UNO [17]
3 years ago
5

If you're driving one and a half miles per minute, slow down by 15 miles per hour, and then reduce your speed by one third, how

fast are you going now
Mathematics
2 answers:
olasank [31]3 years ago
4 0

Answer:

We are moving at 50 mph

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Algebraic Equations.

The first thing we need to do in order to solve this problem is change the initial speed into mph.

\frac{1.5mi}{1min} * 60min =  \frac{90mi}{hour}

Now we subtract the initial speed by 15 mph.

\frac{90mi}{hour} - \frac{15mi}{hour} = \frac{75mi}{hour}

Finally, we need to reduce the current speed by 1/3, this means that the final speed is 2/3 of the current speed. We can calculate this by multiplying the current speed by 2/3 like so,

\frac{75mi}{hour} * \frac{2}{3} = \frac{50mi}{hour}

Finally, we can see that we are moving at 50 mph

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

iogann1982 [59]3 years ago
3 0

1.5 miles per minute is 90 mph.

Slowing down by 15 mph makes 75 mph.

Reduce speed by a third (25 mph) and that makes 50 mph.

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3 years ago
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2 years ago
If Samuel orders four DVDS each dvd costs 9.99 he has 20% discount code and the sales tax is 6.75% what is the total cost
arsen [322]
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3 years ago
Can someone check if this is right please? If not what is the correct way?
Charra [1.4K]

A, B, and C are the coefficients. They are not the terms as you have written now.

A quadratic equation is in the form Ax^2 + Bx + C. Therefore, A = 1, B = 8, and C = -6.

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6 0
3 years ago
In the diagram below, P and Q are points on a circle with centre O.
Gnoma [55]

Answer:

<h2>∠PQT = 72°</h2>

Step-by-step explanation:

According to the diagram shown, ∠OPQ = ∠OQP = 18°. If PQT is a tangent to the circle, it can be inferred that line OQ is perpendicular to line QT. Ths shows that ∠OQT = 90°.

Also from the diagram, ∠OQP + ∠PQT = ∠OQT;

∠PQT  = ∠OQT -  ∠OQP

Given ∠OQP = 18° and ∠OQT = 90°

∠PQT = 90°-18°

∠PQT = 72°

8 0
3 years ago
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