Answer:
Step-by-step explanation:
Volume of Cone =1 \div 3 \times \pi \times r { \times h}^{2}1÷3×π×r×h
2
9.99*4=39.96
39.96*.20=7.992 39.96-7.992=31.968
31.968*.0675=2.1578 31.968+2.1578=
$34.13
A, B, and C are the coefficients. They are not the terms as you have written now.
A quadratic equation is in the form Ax^2 + Bx + C. Therefore, A = 1, B = 8, and C = -6.
The axis of symmetry is found using the equation -b/2a, as you've done. Therefore, the axis of symmetry is -8/2(1) = -4.
Hope this helps!! :)
Answer:
<h2>
∠PQT = 72°</h2>
Step-by-step explanation:
According to the diagram shown, ∠OPQ = ∠OQP = 18°. If PQT is a tangent to the circle, it can be inferred that line OQ is perpendicular to line QT. Ths shows that ∠OQT = 90°.
Also from the diagram, ∠OQP + ∠PQT = ∠OQT;
∠PQT = ∠OQT - ∠OQP
Given ∠OQP = 18° and ∠OQT = 90°
∠PQT = 90°-18°
∠PQT = 72°