-3(5 + 8x) - 20 ≤ -11 |use distributive property: a(b + c) = ab + ac
-15 - 24x - 20 ≤ -11
-35 - 24x ≤ -11 |add 35 to both sides
-24x ≤ 24 |change signs
24x ≥ -24 |divide both sides by 24
x ≥ -1
For this, we use simultaneous equations. Let George's page be g, Charlie's be c and Bill's page be b.
First, <span>George's page contains twice as many type words as Bill's.
Thus, g = 2b.
</span><span>Second, Bill's page contains 50 fewer words than Charlie's page.
Thus, b = c - 50.
</span>If each person can type 60 words per minute, after one minute (i.e. when 60 more words have been typed) <span>the difference between twice the number of words on bills page and the number of words on Charlie's page is 210.
We can express that as 2b - c = 210.
Now we need to find b, since it represents Bill's page.
We can substitute b for (c - 50) since b = c - 50, into the equation 2b - c = 210. This makes it 2(c - 50) - c = 210.
We can expand this to 2c - 100 - c = 210.
We can simplify this to c - 100 = 210.
Add 100 to both sides.
c - 100 + 100 = 210 + 100
Then simplify: c = 210 + 100 = 310.
Now that we know c, we can use the first equation to find b.
b = c - 50 = 310 - 50 = 260.
260 is your answer. I don't know where George comes into it. Maybe it's a red herring!</span>
Answer: The area of the enlargement is 315cm.
Step-by-step explanation:
If the picture has 35cm as the area and it has a length of 7cm then we can find the width by dividing the area by the length.
w= 35/7
w = 5
So in this care the width of the picture in 5cm.
Now is saying that the picture's length has been enlarge or been dilated to 21 cm. To get from 7cm to 21cm you will have to multiply by 3.
In this situation, we will have to multiply the original picture's width by 3 to find it enlargement.
w= 5*3 = 15
The width is 15cm and the length is 21cm so multiply them to find the area.
A = 15 * 21
A = 315cm
<span>helps you find where to put the first digit, when finding the actual quiotient</span>
