Ask question

Ask question

All categories

2 years ago

11

The question is in the image.

1 answer:

zepelin [54]2 years ago

6 0

Answer:

Both are linear functions.

Step-by-step explanation:

There are no same x values in the table and the graph passes the vertical line test.

You might be interested in

andreev551 [17]

Answer:

The hat cost £5 while the a shirt cost £6

Step-by-step explanation:

What I did was Guess and check until I finally found each of there amount.

4 0

3 years ago

HELP MEEEEEEEEEE SOOOOOO EASY PLEASE AND BRANLIEST TOOOOOO (07.04 LC)What is the solution to the equation fraction 1 over 3x = 6

nasty-shy [4]

Answer:

<em>x = 2</em>

<em>divide each term by 3 and simplify.</em>

7 0

3 years ago

Read 2 more answers

Kamau bought 50 kg of sugar for sh 4000

Nana76 [90]

Answer:

Profit % =50%

Step-by-step explanation:

Cost of 50 kg = sh 4000

Selling price of 1kg = sh 120

Selling price of 50 kg = sh 6000

$profit \% = \frac{Selling \ price - cost \ price}{cost \ price} \times 100\\$

$=\frac{6000 - 4000}{4000} \times 100\\\\=\frac{2000}{4000} \times 100\\\\=\frac{1}{2} \times 100\\\\=50 \%$

7 0

2 years ago

Cubic yards of concrete will be required for 14 parking lot light pole standards

riadik2000 [5.3K]

Using conversion of units and volume of a cylinder, it is found that 23.17 cubic yards of concrete are needed, option D.

The volume of a cylinder of radius r and height h is given by:

$V = \pi r^2h$

In this problem:

We want the volume in cubic yards, thus, the units of radius and height have to be in yards.
32 inches in diameter, thus 16 inches of radius. Since each inch has 0.0278 yards, this is a radius of 0.44 yards, thus $r = 0.44$ .
Height of 8 feet, and since each feet has 0.33 yards, this is a height of 2.67 yards, thus $h = 2.67$
14 poles, thus the volume is multiplied by 14.

Then:

$V = 14\pi(0.44)^2(2.67) = 23.17$

23.17 cubic yards of concrete are needed, option D.

A similar problem is given at brainly.com/question/22789697

3 0

2 years ago

Lines k and n intersect on the y-axis

avanturin [10]

a) The equation of line k is:

$y = -\frac{202}{167}x + \frac{598}{167}$

b) The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

The equation of a line, in <u>slope-intercept formula</u>, is given by:

$y = mx + b$

In which:

m is the slope, which is the rate of change.
b is the y-intercept, which is the value of y when x = 0.

Item a:

Line k intersects line m with an angle of 109º, thus:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

In which $m_1$ and $m_2$ are the slopes of <u>k and m.</u>

Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

$m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}$

The tangent of 109 degrees is $\tan{109^{\circ}} = -\frac{29}{10}$
Thus, the slope of line m is found solving the following equation:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

$-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}$

$m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2$

$m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}$

$\frac{167m_2}{80} = \frac{-202}{80}$

$m_2 = -\frac{202}{167}$

Thus:

$y = -\frac{202}{167}x + b$

It goes through point (-2,6), that is, when $x = -2, y = 6$ , and this is used to find b.

$y = -\frac{202}{167}x + b$

$6 = -\frac{202}{167}(-2) + b$

$b = 6 - \frac{404}{167}$

$b = \frac{6(167)-404}{167}$

$b = \frac{598}{167}$

Thus. the equation of line k, in slope-intercept formula, is:

$y = -\frac{202}{167}x + \frac{598}{167}$

Item b:

Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

$-\frac{202}{167}m = -1$

$m = \frac{167}{202}$

Then

$y = \frac{167}{202}x + b$

Also goes through point (-2,6), thus:

$6 = \frac{167}{202}(-2) + b$

$b = \frac{(2)167 + 202(6)}{202}$

$b = \frac{1546}{202}$

The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

A similar problem is given at brainly.com/question/16302622

7 0

2 years ago