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Ierofanga [76]
3 years ago
6

Police use photographs of various facial features help witnesses identify suspects. One basic identification kit contains 195 ha

irlines, 99 eyes and eyebrows, 89 noses, 105 mouths, and 74 chins and cheeks. A witness can clearly remember the hairline and the eyes and eyebrows of a suspect. How many (no commas needed) different faces can be produced with this information?
Mathematics
1 answer:
algol [13]3 years ago
7 0

Answer:

the kit can produce 99*89*105*74 = 68,461,470 faces

Step-by-step explanation:

Hope this helps : )

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Which statement about the inequality 215<235 is true? On the vertical number line, 215 is located below 235. On the vertical
masha68 [24]
On vertical line 215 is located below 235
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Find the slope for the line through each pair of points (-18,-20) (-18,-15) NEED ASAP
nirvana33 [79]

Answer:

Distance

5

Midpoint

(−18,−17.5)

Slope

Inf∈ity

Step-by-step explanation:

no solution

4 0
3 years ago
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Two intelligent, honest students are sitting together at lunch one day when their math teacher hands them each a card. “your car
Lady bird [3.3K]
Answer: The loser's card shows 6.

Explanation: Let's start by naming the first student A and the second student B.
Since the product of A and B are either 12, 15, or 18, let's list every single possibility, the first number being A's number and the second number being B's number.

1     12
1     15
1     18
2     6
2     9
3     4
3     5
3     6
4     3
5     3
6     2
6     3
9     2
12  1
15  1
18  1

Now, the information says that A doesn't know what B has, so we can immediately cross off all of the combinations that have the integer appearing once and once ONLY off, because if it happened once only, A would know of it straight away. Now, our sample space becomes much smaller.

1     12
1     15
1     18
2     6
2     9
3     4
3     5
3     6
6     2
6     3

Using this same logic, we know that we can cross off all of the digits that occur only once in B's column.

2     6
3     6

Now, A definitely knows what number B has because there is only one number left in B. Hence, we can conclude that the loser, B, has the integer 6.
4 0
3 years ago
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ziro4ka [17]

Answer:

x = 4 or x = 1 or x = -2 or x = -3/2

Step-by-step explanation:

Solve for x over the real numbers:

2 x^4 - 3 x^3 - 21 x^2 - 2 x + 24 = 0

The left hand side factors into a product with four terms:

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Split into four equations:

x - 4 = 0 or x - 1 = 0 or x + 2 = 0 or 2 x + 3 = 0

Add 4 to both sides:

x = 4 or x - 1 = 0 or x + 2 = 0 or 2 x + 3 = 0

Add 1 to both sides:

x = 4 or x = 1 or x + 2 = 0 or 2 x + 3 = 0

Subtract 2 from both sides:

x = 4 or x = 1 or x = -2 or 2 x + 3 = 0

Subtract 3 from both sides:

x = 4 or x = 1 or x = -2 or 2 x = -3

Divide both sides by 2:

Answer:  x = 4 or x = 1 or x = -2 or x = -3/2

7 0
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snow_lady [41]

Answer:

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