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zlopas [31]
3 years ago
6

The length of a rectangle is 4 in longer than its width. if the perimeter of the rectangle is 28 in , find its area.

Mathematics
1 answer:
ra1l [238]3 years ago
7 0
The area is 45 inches squared

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Find 2.65 + 3.12 write your answer as a decimal
Naily [24]
The answer is 5.77 i hope this helps
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3 years ago
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A factory inspector found flaws in 4 out of 22 wooden boxes. Considering this data, how many flawed
Anna11 [10]
The answer is 8. Hope this helps.
6 0
3 years ago
Which results only in a horizontal compression of Y = by a factor of 6?
elena55 [62]

Answer:

Y = 6*y

Step-by-step explanation:

We have Y = b * y by a factor of 6.

That is, b = 6.

now, to find what results only in a horizontal compression of y = b * y by a factor of 6.

By transformation rule, the function would be a horizontal compression f (a * x) if a> 1.

Therefore, knowing the above, the answer would be:

Y = 6 * y

3 0
3 years ago
[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation
irina1246 [14]

Answer:

y=-\frac{158}{579}

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]

And the vector B is formed with the solution of each equation of the system:b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called A_{2}.

A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]

The value of y using Cramer's rule is:

y=\frac{det(A_{2}) }{det(A)}

Find the value of the determinant of each matrix, and divide:

y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}

y=-\frac{158}{579}

7 0
4 years ago
F(x)=-(2) * + 4<br> What is the range of this function
Valentin [98]

Answer: f(x) = 2

Step-by-step explanation:

I think this is the answer I hope it helps u

4 0
3 years ago
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