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BartSMP [9]
2 years ago
12

I need help please HELP ME PLEASE HELPPP

Mathematics
1 answer:
forsale [732]2 years ago
8 0
We see that the total legnth is 9 and 5/8 inches
each piece is 1 and 3/8 inches long
there are 7 pieces

a board that is 9 and 5/8 inches total legnth is cut into pieces that measure 1 and 3/8 inches is cut into 7 pices

not A, should be cut into 7 pices, not 9 and 5/8
not B because the board is 9 and 5/8 long


the answer is C
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A number is decreased by 40% to 525. what is the original amount?​
zhenek [66]

Answer:

875

Step-by-step explanation:

lets assume the original amount X

the new amount = X - ( X × 40% )

525 = (60 × X) ÷ 100

X = ( 525 × 100 ) ÷ 60

<u>X = 875</u>

6 0
2 years ago
Read 2 more answers
Need help really badly please help .
Harlamova29_29 [7]

Answer:

sin s = 36 / 42 = 18 / 21 = 6/ 7

sin R = 14 / 42 = 7 / 21 = 1 / 3

cos s = 14 / 42 = 1 / 3

cos R = 36 / 42 = 6 / 7

4 0
2 years ago
Question 1 of 25
aleksklad [387]
SAS i believe :) sorry if im wrong!
8 0
2 years ago
A shelf is built on a wall, as shown below. What is the value of x?<br> (2x+1) + (3x-1)
Hoochie [10]

Answer:

x = 18

Step-by-step explanation:

We need to find the value of x.

We know that the sum of angles of a triangle is equal to 180°. So, using this property,

2x+1+3x-1+90 = 180

2x+3x = 180-90

5x = 90

x = 18

So, the value of x is equal to 18.

6 0
2 years ago
Given the position of the particle, what the position(s) of the particle when it’s at rest
choli [55]

The position function of a particle is given by:

X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t

The velocity function is the derivative of the position:

\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}

The particle will be at rest when the velocity is 0, thus we solve the equation:

2t^2-9t-18=0

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Substituting:

\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}

We have two possible answers:

\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

undefined

6 0
1 year ago
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