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WINSTONCH [101]
3 years ago
15

Simplify this problem

Mathematics
1 answer:
ikadub [295]3 years ago
7 0

Answer:

\boxed{  \frac{ \sqrt[3]{ {x}^{11} } }{4} }

Step-by-step explanation:

=  >  \frac{ {x}^{4} }{ \sqrt[3]{64x} }  \\  \\  =  >  \frac{ {x}^{4} }{ {(64x)}^{ \frac{1}{3} } }  \\  \\  =  >  \frac{ {x}^{4} }{ ({64}^{ \frac{1}{3} }  )\times  ({x}^{ \frac{1}{3} } )}  \\  \\  =  >  \frac{ {x}^{4} }{ ({( {4}^{3} )}^{ \frac{1}{3} }) \times(  {x}^{ \frac{1}{3} }  )}  \\  \\  =  >   \frac{ {x}^{4} }{ ({4}^{ \cancel{3} \times  \frac{1}{ \cancel{3}} } ) \times(  {x}^{ \frac{1}{3} }  )}   \\  \\  =  >  \frac{ {x}^{4} }{4 {x}^{ \frac{1}{3} } }  \\  \\  =  >  \frac{ {x}^{4 -  \frac{1}{3} } }{4}  \\  \\  =  >  \frac{ {x}^{ \frac{12 - 1}{3} } }{4}  \\  \\  =  >  \frac{ {x}^{ \frac{11}{3} } }{4}  \\  \\  =  >   \frac{ \sqrt[3]{ {x}^{11} } }{4}

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strojnjashka [21]

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<h2>Final Answer: 1/10</h2>

Alternate Forms:

  • Decimal: 0.1

Hope it helps

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MrRa [10]

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Step-by-step explanation:

(2scos(pi/6) +2i sin(pi/2))^n =-64...n=?

(2scos(pi/6) +2i sin(pi/2))^n =-64...n=?

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and you get

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