4 x 1 + 1 x 1/100 + 9 x 1/1000 in standard form

Please help me:) I don’t know what to do

Cloud [144]

Answer:

8 family members. Average of 2.6 fish per person.

Step-by-step explanation:

How many family members caught fish? Count only those members who caught at least 1 fish (that's all of them, because nobody caught 0 fish!).

3 + 1 + 0 + 4 = 8 family members.

Average number of fish caught per person. This is the total number of fish caught divided by the total number of people.

This is a little bit tricky because, for example, 4 people caught 4 fish, making 4 x 4 = 16 fish caught.

Multiply number of fish (column 1) by the number of people (column 2):

1 x 3 + 2 x 1 + 3 x 0 + 4 x 4 = 3 + 2 + 0 + 16 = 21 fish caught.

21 fish. 8 people. On average, that is 21 / 8 = 2.625 which rounds to 2.6 fish per person.

Hint: the word "per" means divide, so "fish per person" tells you to divide the total number of fish by the total number of people.

Good Luck!

5 0

1 year ago

Businesses deposit large sums of money into bank accountsImagine an account with $10 million dollars in it.

adoni [48]

again, let's assume daily compounding means 365 days per year.

$~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ t=years\dotfill &1 \end{cases} \\\\\\ I = (10000000)(0.0212)(1)\implies \boxed{I=212000}$

$~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{daily, thus 365} \end{array}\dotfill &365\\ t=years\dotfill &1 \end{cases}$

$A=10000000\left(1+\frac{0.0212}{365}\right)^{365\cdot 1}\implies A\approx 10214256.88 \\\\\\ \underset{\textit{earned interest amount}}{10214256.88~~ - ~~10000000 ~~ \approx ~~ \boxed{214256.88}}$