There are four nickels, three dimes, and three quarters in your pocket. You randomly pick three coins and place them on a counte
r. The first coin is a nickel, the second is a dime, and the third is a quarter. Find the probability of this occurring.
1 answer:
Total coins = 10 ( 4 + 3 + 3 = 10).
The probability of picking a nickel first = 4/10 = 2/5 ( 4 nickels out of 10 total).
The probability of picking a dime second = 3/9 = 1/3 ( 3 dimes out of 9 coins left).
The probability of picking the third coin as a quarter = 3/8 ( 3 quarters out of 8 coins left).
The probability of picking all three in that order = 2/5 x 1/3 x 3/8 = 1/20
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f(-2) = -1
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-2 is x, so replace x as -2 into the equation
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f (-2) = -1
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Yes, the distance between the points would be 8
Step-by-step explanation:
Since the y is the same, you can just find the distance between 12 and 4
12-4=8

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