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postnew [5]
3 years ago
10

Who knows how to do this 8 cos x+3=0 ??

Mathematics
1 answer:
maw [93]3 years ago
6 0
You want to find the measure of angle x.  Rearrange the given 8 cos x+3=0 as <span>8 cos x= -3, or cos x = -3 / 8, or cos x = -0.375.  

Use the arccos function (inverse cosine) to find the value of x in radians and in degrees.

Since the cosine function is negative only in Quadrants II and III, focus on the following possible ranges:  Quadrant II:  90 < x < 180 and
Quadrant III:  180 < x < 270.

Example:  using my calculator to obtain the inverse cosine of -0.375, I got x = 1.96 radians.  Convert this into degrees if desired.  Draw a ray showing this angle.  Reflect this ray across the horiz. axis to obtain the angle in Q III.</span>
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1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30+31+32+33+34+35+36+37+38+39+40+41+42+43+44+45+46
skelet666 [1.2K]

Answer:

1275

Step-by-step explanation:

Because 1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30+31+32+33+34+35+36+37+38+39+40+41+42+43+44+45+46+47+48+49+50 = 1275

Also this was a weird but easy question!

5 0
3 years ago
Read 2 more answers
Use three different values of n to demonstrate that 2n + 3n is equivalent to 5n.
Rainbow [258]
You could use 10, 6 and 7.

Using ten would have them all equal 50, using 6 would have them all equal 30 and using 7 would have them all equal 35.

Hope this helps!
5 0
2 years ago
Read 2 more answers
Construct a​ 99% confidence interval for the population​ mean, mu. Assume the population has a normal distribution. A group of 1
Zarrin [17]

Answer:

99% confidence interval for the population​ mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population​ mean is given by;

         P.Q. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean age of selected students = 22.4 years

             s = sample standard deviation = 3.8 years

             n = sample of students = 19

             \mu = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population​ mean, \mu is ;

P(-2.878 < t_1_8 < 2.878) = 0.99  {As the critical value of t at 18 degree of

                                                freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } < 2.878) = 0.99

P( -2.878 \times {\frac{s}{\sqrt{n} } } < {\bar X - \mu} < 2.878 \times {\frac{s}{\sqrt{n} } } ) = 0.99

P( \bar X -2.878 \times {\frac{s}{\sqrt{n} } < \mu < \bar X +2.878 \times {\frac{s}{\sqrt{n} } ) = 0.99

<u>99% confidence interval for</u> \mu = [ \bar X -2.878 \times {\frac{s}{\sqrt{n} } , \bar X +2.878 \times {\frac{s}{\sqrt{n} } ]

                                                 = [ 22.4 -2.878 \times {\frac{3.8}{\sqrt{19} } , 22.4 +2.878 \times {\frac{3.8}{\sqrt{19} } ]

                                                 = [19.891 , 24.909]

Therefore, 99% confidence interval for the population​ mean is [19.891 , 24.909].

6 0
3 years ago
What is 14145 divided by 23?
Kobotan [32]

Answer:

615

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What defines a line segment
Stolb23 [73]
A line segment is defined as the set of numbers that is contained in a line between the two endpoints.
4 0
3 years ago
Read 2 more answers
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