Given:
Consider the complete question is "A speed walker covered 
mi in 
hour. How far will he walk in 3/4 hours if he walks twice as fast?"
A speed walker covered mi in hour.
To find:
Distance covered by him if in 3/4 hour if he walks twice as fast.
Solution:
We have,
It means a speed walker covered 
mi in hour.
If the speed is twice then he can cover double distance is same time.
Distance covered by him if in 3/4 hour if he walks twice as fast is
Therefore, distance covered by him is 9 mi.
6^2 + 17 + 12
First, let's start with
. Basically, the '2' above the 6 indicates that the number appears twice in multiplying.
can be described as 6 × 6 as well. 36 should be your answer for 6 squared.
Second, our problem should look like: 36 + 17 + 12. One can simply do this on a calculator or count on their fingers. Once you add all of the numbers up, you should get 65.
Answer:
Answer:
Ф = 
Step-by-step explanation:
It is a bit difficult to input the work here, so I uploaded an image
- First we can use the trig identities to change sec²(Ф) to tan²(Ф) + 1
- Then we can combine like terms
- Then we can factor this as a polynomial function
- Then we can set each term equal to zero and solve for Ф
- The first term tan(Ф) - 2 = 0 has no solution because tan(Ф) ≠ -2 anywhere
- The second term tan(Ф) - 1 = 0 has two solutions of
and 
so these are the solutions to the problem
Answer:
-7x - 6
Step-by-step explanation:
1
Distribute
(−2+5)−1(6+4)+(−7)
(−2+5)−6−4+(−7)
2
Eliminate redundant parentheses
(−2+5)−6−4+(−7)
−2+5−6−4+−7
3
Add the numbers
−2+5−6−4+−7
−2−6−6+
4
Combine like terms
−2−6−6+
Answer:
−7−6
