we are given
to write the sets of points from -2 to 5 but excluding 2 and 5 as a union of intervals
so, first interval is
-2 to 2 by excluding 2
[-2,2)
Second interval is
2 to 5 by excluding 2 and 5
so, we can write as
(2,5)
now, we can find total interval
we get
[-2,2) ∪ (2,5)..............Answer
Answer:
A i think
Step-by-step explanation:
This is excercise number 4
Answer:
Given the expression:
1.
![-4^2](https://tex.z-dn.net/?f=-4%5E2)
we know:
![4^2 = 4 \times 4 = 16](https://tex.z-dn.net/?f=4%5E2%20%3D%204%20%5Ctimes%204%20%3D%2016)
then;
![-4^2 = -16](https://tex.z-dn.net/?f=-4%5E2%20%3D%20-16)
Therefore, the value of expression
is -16 i.e negative.
2.
![(-4)^2](https://tex.z-dn.net/?f=%28-4%29%5E2)
we know:
![4^2 = 4 \times 4 = 16](https://tex.z-dn.net/?f=4%5E2%20%3D%204%20%5Ctimes%204%20%3D%2016)
![(-1)^2 = 1](https://tex.z-dn.net/?f=%28-1%29%5E2%20%3D%201)
then;
![(-4)^2 = (-1)^2 \cdot (4)^2= 16](https://tex.z-dn.net/?f=%28-4%29%5E2%20%3D%20%28-1%29%5E2%20%5Ccdot%20%284%29%5E2%3D%2016)
Therefore, the expression
is 16 i.e Positive.
3.
![4^2](https://tex.z-dn.net/?f=4%5E2)
we know:
![4^2 = 4 \times 4 = 16](https://tex.z-dn.net/?f=4%5E2%20%3D%204%20%5Ctimes%204%20%3D%2016)
then;
![4^2 = 16](https://tex.z-dn.net/?f=4%5E2%20%3D%2016)
Therefore, the expression
is 16 i.e Positive.
Answer:
D. 7
Step-by-step explanation:
brainiest plz