Answer:
x=110°
y=49°
Step-by-step explanation:
Here consider ΔABD and ΔBCD as seperate.
In ΔABD
Given AB=AD which means that it is an isosceles triangle.
∠ABD=∠ADB
∠ADB=35°
In ΔABD sum of the angles =180°
∠BAD + 35° + 35° =180°
x=180°-70°=110°
In ΔBCD
Given BC=DC which means ΔBCD is an isosceles triangle.
∠CBD=∠CDB
∠CDB=y
∠CBD=y
In ΔBCD the sum of the angle =180°
y° + y° + 82°=180°
2y°=98°
y=49°
Angle RQS = 72
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Answer:
x= -1/4
Step-by-step explanation:
Expand.
8x+2-3=4x-2
Simplify 8x+2-3 to 8x-1.
8x-1=4x-2
Subtract 4x from both sides.
8x−1−4x=−2
Simplify 8x-1-4x to 4x-1.
4x−1=−2
Add 1 to both sides.
4x=−2+1
Simplify -2+1 to −1.
4x=−1
Divide both sides by 4.
x= -1/4