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sergeinik [125]
3 years ago
5

Identify the ellipses, represented by equations, whose eccentricities are less than 0.5

Mathematics
2 answers:
jok3333 [9.3K]3 years ago
8 0

Answer:

1, 4 and 6 for plato

Step-by-step explanation:

ozzi3 years ago
3 0

Answer:

See explanation

Step-by-step explanation:

Hello, we cannot see the ellipse equations.

The eccentric of an ellipse is given by:

e =  \frac{c}{a}

Assuming the equations are:

\frac{ {x}^{2} }{25}  +  \frac{ {y}^{2} }{16}  = 1

Then a²=25 and b²=16

{c}^{2}  =  {a}^{2}  -  {b}^{2}

{c}^{2}  = 25 - 16

{c}^{2}  =  {3}^{2}

c = 3

The eccentricity is:

e =  \frac{3}{5}  = 0.6

If the ellipse has equation,

\frac{ {x}^{2} }{ {5}^{2} }  +  \frac{ {y}^{2} }{ {3}^{2} }  = 1

then the this time, we have a=5 and b=3.

This means that:

{c}^{2}  =  {a}^{2}  -  {b}^{2}

{c}^{2}  =  {5}^{2}  -  {3}^{2}

{c}^{2}  =  {4}^{2}

c = 4

c =  \frac{4}{5}  = 0.8

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The fastest way to find the missing endpoint is to determine the distance from the known endpoint to the midpoint and then performing the same transformation on the midpoint.  In this case, the x-coordinate moves from 4 to 2, or down by 2, so the new x-coordinate must be 2-2 = 0.  The y-coordinate moves from 4 to -5, or down by 9, so the new y-coordinate must be -5-9 = -14.

 

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