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nikdorinn [45]
3 years ago
8

1 Fifty-five students, 4 teachers, and 3

Mathematics
1 answer:
Mrac [35]3 years ago
6 0
They will bring $814 dollars all together
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nata0808 [166]

Answer:

im sorry but whats the question exactly i will try to awnser it

Step-by-step explanation

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3 years ago
Find the quotient. 28,134 ÷ 47
Marizza181 [45]

Answer:

28,134 / 47 = 598.6

Step-by-step explanation:

8 0
2 years ago
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D₁ vide using x² - 2x² 2× +3× -5 by ×-3 using synthetic division. <br>​
Vaselesa [24]

Answer:

Step-by-step explanation:

I think you are trying to use synthetic division for

x^{4} -2x^{3} -2x^{2} +3x-5 divided by x-3

First  

x -3 = 0 , make it equal to 0 and add 3 to both sides

x = 3

Then we write all the coefficients and continue with

a pattern of multiply by 3 and add to the next coefficient.

See attachment.

5 0
1 year ago
Select the correct answer from each drop-down menu. A teacher is making a history test composed of the same number of multiple-c
GaryK [48]

Answer:

Step-by-step explanation:idbdhides by

7 0
3 years ago
Suppose that two teams play a series of games that ends when one of them has won ???? games. Also suppose that each game played
Musya8 [376]

Answer:

(a) E(X) = -2p² + 2p + 2; d²/dp² E(X) at p = 1/2 is less than 0

(b) 6p⁴ - 12p³ + 3p² + 3p + 3; d²/dp² E(X) at p = 1/2 is less than 0

Step-by-step explanation:

(a) when i = 2, the expected number of played games will be:

E(X) = 2[p² + (1-p)²] + 3[2p² (1-p) + 2p(1-p)²] = 2[p²+1-2p+p²] + 3[2p²-2p³+2p(1-2p+p²)] = 2[2p²-2p+1] + 3[2p² - 2p³+2p-4p²+2p³] =  4p²-4p+2-6p²+6p = -2p²+2p+2.

If p = 1/2, then:

d²/dp² E(X) = d/dp (-4p + 2) = -4 which is less than 0. Therefore, the E(X) is maximized.

(b) when i = 3;

E(X) = 3[p³ + (1-p)³] + 4[3p³(1-p) + 3p(1-p)³] + 5[6p³(1-p)² + 6p²(1-p)³]

Simplification and rearrangement lead to:

E(X) = 6p⁴-12p³+3p²+3p+3

if p = 1/2, then:

d²/dp² E(X) at p = 1/2 = d/dp (24p³-36p²+6p+3) = 72p²-72p+6 = 72(1/2)² - 72(1/2) +6 = 18 - 36 +8 = -10

Therefore, E(X) is maximized.

6 0
2 years ago
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