Question

The

Answer 1

Answer:   $\huge\boxed{x=3\frac{1}{3} \quad ;\quad y=-3}$

Step-by-step explanation:

$\displaystyle\ \Large \boldsymbol+\ \left \{ {{6x+4y=8} \atop {-4y=12}} \right. \Longrightarrow\\\\\\ 6x+ 4y\!\!\!\!\!\diagup-4y\!\!\!\!\!\diagup=12+8 \\\\6x=20 \\\\x=\frac{20}{6} =\frac{10}{3} =3\frac{1}{3} \quad ; \quad y=-3$

Answer 2

6x + 4y = 8
-4y = 12

6x + 4y = 8
y = 12/-4 = -3

6x + 4(-3) = 8
y = -3

6x -12 = 8
y = -3

x = (8+12)/6 = 10/3
y = -3 i guess