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vredina [299]
3 years ago
8

−x=5 x = wut is thi$

Mathematics
1 answer:
Vlada [557]3 years ago
5 0

Answer:

x = -5

Step-by-step explanation:

-x = 5

*-1   *-1

-x * -1 = x

5 * -1 = -5

x = -5

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I'll mark as brainliest if you get the correct answer WITH step by step explaination.​
elena-s [515]

<em>ANSWER:</em>

value of "a" is: a= -b√3+7+4√3

value of "b" is:  \frac{-a\sqrt{3}+7\sqrt{3} }{y} +4

<em></em>

<em>STEP-BY-STEP EXPLANATION:</em>

<h2><u>how to get the value of "a":</u></h2><h2><u /></h2>

1. <u>(</u>rationalize the denominator)

<u>(2 + √3) </u><u>× (2 + √3)</u> =a + b√3

2. (write the repeated multiplication in exponential form)

<u>(2 + √3)²</u> =a + b√3

3. (use (a + b)² = a² + 2ab + b²  to expand the expression)

<u>4 </u>+ 4√3 + <u>3</u> = a + b√3

4. ( add the numbers)

7 + 4√3 = <u>a</u> + b√3

5. (move the <u>variable</u> to the left-hand side and change its sign. then, move the <u>constants</u> to the right-hand side and change their signs)

<h3><u>-a</u> + 7 + 4√3 = b√3  ⇔ -a = b√3 <u>-7 - 4√3</u></h3>

<u></u>

6. (change the signs on both sides of the equation)

a = -b√3 + 7 + 4√3

<h2><u>how to get the value of "b":</u></h2><h2><u /></h2>

1. (rationalize the denominator. then, use the commutative property to reorder the terms)

(2 + \sqrt{3}) × (2 + \sqrt{3} ) = <u>a + b</u>\sqrt{3}   →  <u>(2 + </u>\sqrt{3}<u>) × (2 +</u>\sqrt{3}<u> )</u> = a + \sqrt{3}b

2. (write the repeated multiplication in exponential form)

<u>(2 + √3)²</u> =a + \sqrt{3}b

3. (use (a + b)² = a² + 2ab + b²  to expand the expression)

<u>4</u> + 4\sqrt{3} + <u>3</u> = a + \sqrt{3}b

4. (add the numbers)

7 + 4 \sqrt{3} = a + \sqrt{3}b

5. (move the expression to the left-hand side and change its sign. then, move the <u>constants</u> to the right-hand side and change their signs)

- \sqrt{3}b + 7  + 4 \sqrt{3} = a  → -\sqrt{3}b = a - 7 - 4\sqrt{3}

6. (divide both sides of the equation by -\sqrt{3})  

b = - \frac{a}{\sqrt{3} }  + \frac{7}{\sqrt{3}} + 4

7. (rationalize the denominator)

b = b=-\frac{a\sqrt{3} }{\s3}} +\frac{7\sqrt{3} }{{3} } +4

8. (write all numerators above the common denominator)

b =  \frac{-a\sqrt{3}+7\sqrt{3} }{y} +4

there you go! I hope this helped. goodluck! :)

7 0
3 years ago
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