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Svetllana [295]
3 years ago
14

9) Amanda is building a garden in her yard. She

Mathematics
1 answer:
Gnom [1K]3 years ago
8 0

Answer:

15

Step-by-step explanation:

3 feet long

5 feet wide

5 × 3 ft = 15

Amanda would have 15 feet of flowers

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Multiply: (sqrt10 +2 sqrt8)(sqrt10-2 sqrt8)
vesna_86 [32]

Answer:

(√10 +2√8)(√10 -2√8)=

(10 -8√5 + 8√5 -32)

10+0-32

10-32

= -22

Hope this helps.

6 0
3 years ago
They have a total of w dollars to buy 5 tickets each ticket costs 15 dollars
Dmitrij [34]

Answer:

$75

Step-by-step explanation:

If they have a total of w dollars to buy 5 tickets, and each ticket costs 15 dollars, $15 x 5 tickets = $75.

3 0
2 years ago
Read 2 more answers
In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the
earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

<em>C</em> = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events <em>A</em>, <em>B</em> and <em>C</em> are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

7 0
3 years ago
3x-9 when x=3<br> Solve this
Citrus2011 [14]

Answer:

0

Step-by-step explanation:

3x - 9 if x = 3

Substitute:

3(3) - 9 =

9 - 9 = 0

This can be written as a function: f(x) = 3x - 9

f(3) = 3x - 9

f(3) = 3(3) - 9

f(3) = 9 - 9

f(3) = 0

-Chetan K

3 0
3 years ago
Simplify the following expression:
Keith_Richards [23]

Answer:

Step-by-step explanation:

-2(2)-1+1(1)-1(-1)

Do multiplication

-4-1+1+1

Now add/subtract

-5+2

-3

6 0
3 years ago
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