You have to square the binomial.
(x^3 + 4y) (x^3 + 4y)
Using FOIL:
x^9 + 4(x^3)y + 4(x^3)y + 16y^2
x^9 + 8(x^3)y + 16y^2

You could also use the formula: (a+b)^2 = (a^2 + 2ab + b^2).

6 0

3 years ago

A grocer wants to mix two kinds of coffee. One kind sells for $1.55 per pound, and the other sells for $2.80 per pound. He wants

anastassius [24]

9.5 or 9 1/2 if you want them both to be an equal mix

7 0

3 years ago

Due to normality, the formula for computing z is the same for a single data value, as it is

katrin2010 [14]

Using the <u>Central Limit Theorem</u>, the statement is false, as for the averages of the data values for a sample group, the standard error is $s = \frac{\sigma}{\sqrt{n}}$ , hence, the formula is:

$Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

While for a single value, it is:

$Z = \frac{X - \mu}{\sigma}$

In a normal distribution with mean and standard deviation , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

Hence, the formulas are different, and for an average of the data values for a sample group it is:

$Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

A similar problem is given at brainly.com/question/24663213

8 0

2 years ago