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qwelly [4]
3 years ago
12

Bradley and Kelly are out flying kites at a park one afternoon. A model of Bradley and Kelly’s kites are shown below on the coor

dinate plane as kites BRAD and KELY respectively. Which statement is correct about the two kites?
A. They are similar because BR:DB is 1:2 and KE:YK 1:2.
B. They are similar because BR:DB is 1:5 and KE:YK is 1:5.
C. They are not similar because BR:DB is 1:5 and KE:YK is 1:2.
D. They are not similar because BR:DB is 1:2 and KE:YK is 1:5.
Mathematics
1 answer:
PtichkaEL [24]3 years ago
6 0
I think you forgot to attach the diagram of the kites. I am answering the question based on my knowledge and research. "<span>They are not similar because BR:DB is 1:2 and KE:YK is 1:5" is the statement that is correct about the two kites. The correct option among all the options that are given in the question is the last option or option "D". </span>
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Ava and Kelly ran a road race, starting from the same place at the same time. Ava ran at an average speed of 6 miles per hour. K
Zepler [3.9K]
<h2>Hello!</h2>

The answer is:

Ava and Kelly will be 3/4 mile apart after 0.375 hours.

<h2>Why?</h2>

To calculate when will Ava and Kelly be 3/4 mile apart, we need to write the equations for both Ava's and Kelly's positions.

Writing the equations we have:

For Ava:

x_A=x_o+v_ot\\\\x_A=0+v_o*t\\\\x_A=v_{o(ava)*t

For Kelly:

We need to calculate when Kelly will be 3/4 mile apart becase is running faster than Ava, so, writing the equation we have:

x_K=x_A+\frac{3}{4}mile=x_o+v_{o(Kelly)}*t

Now, substituting the equation for Ava into the equation for Kelly, we have:

x_A+\frac{3}{4}mile=x_o+v_{o(Kelly)}*t

v_{o(ava)*t+\frac{3}{4}mile}=x_o+v_{o(Kelly)}*t

v_{o(ava)*t+0.75mile}=x_{o}+v_{o(Kelly)}*t\\\\6mph*t+0.75mile=8mph*t\\\\0.75mile=2mph*t\\\\t=\frac{0.75miles}{2mph}=0.375hours

To prove  that the result is correct, we just need to substitute the obtained value for time into both equations, so, substutiting we have:

For Ava:

x_A=v_{o(ava)*t=6mph*0.375hours=2.25miles

For Kelly:

x_K=v_{o(Kelly)}*t=8mph*0.375=3miles

There is a difference of 0.75 miles or 3/4 mile between Ava and Kelly, so, the obtained value for time is correct.

Therefore, we have that Ava and Kelly will be 3/4 mile apart after 0.375 hours.

Have a nice day!

5 0
3 years ago
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