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Helen [10]
2 years ago
7

Please help me thanks

Mathematics
2 answers:
STALIN [3.7K]2 years ago
8 0
I only know 4 and 5: 1/2
Westkost [7]2 years ago
3 0

Answer:

3) 1/6

4) 1/2

5) 1/2

6) 1/3

7) 1/2

8) 1/3

9) 0

10) 1

11) 5/6

12) 1/3

Step-by-step explanation:

3) There is only one 2 on a die. Thus, the probability would be 1/6.

4) There are 3 even numbers on a die (2, 4, 6). Thus, the probability would be 3/6 which simplifies down to 1/2.

5) There are also 3 odd numbers on a die (1, 3, 5). Thus, the probability would be 3/6, which again simplifies down to 1/2.

6) There are only 2 numbers greater than 4 on a die (5, 6). This makes the probability 2/6, which simplifies to 1/3.

7) There are 3 numbers less than 4 on a die (1, 2, 3). This makes the probability 1/2.

8) The probability of getting a 6 or 2 is 1/3. This is because when the probability statement says "or" you add the probabilities of the individual events to get the probability. In this case it would be 1/6 + 1/6 which equals 2/6, simplified to 1/3.

9) The probability of rolling a 7 is 0. There is no 7 on the die, so you would not be able to roll a 7.

10) All the numbers on a die are less than 10, this makes the probability 1.

11) There are 5 other numbers that aren't "5" on the die, this makes the probability 5/6.

12) Composite numbers are a number that can be formed by multiply 2 smaller numbers together. There are only 2 on a die, 4 and 6. Four is a composite number because 2*2 = 4. Six is a composite number because 3*2 = 6. Therefore, the probability will be 1/3 (2/6).

Hope this helps!! If you have any questions about my work please let me know down in the comments.

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Answer:

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Step-by-step explanation:

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Hope this helps you

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How do you do this question?
ElenaW [278]

x*y' + y = 8x

y' + y/x = 8 .... divide everything by x

dy/dx + y/x = 8

dy/dx + (1/x)*y = 8

We have something in the form

y' + P(x)*y = Q(x)

which is a first order ODE

The integrating factor is u(x) = e^{\int P(x)dx} = e^{\int (1/x) dx} = e^{\ln(x)} = x

Multiply both sides by the integrating factor (x) and we get the following:

dy/dx + (1/x)*y = 8

x*dy/dx + x*(1/x)*y = x*8

x*dy/dx + y = 8x

y + x*dy/dx = 8x

Note the left hand side is the result of using the product rule on xy. We technically didn't need the integrating factor since we already had the original equation in this format, but I wanted to use it anyway (since other ODE problems may not be as simple).

Since (xy)' turns into y + x*dy/dx, and vice versa, this means

y + x*dy/dx = 8x turns into (xy)' = 8x

Integrating both sides with respect to x leads to

xy = 4x^2 + C

y = (4x^2 + C)/x

y = (4x^2)/x + C/x

y = 4x + Cx^(-1)

where C is a constant. In this case, C = -5 leads to a solution

y = 4x - 5x^(-1)

you can check this answer by deriving both sides with respect to x

dy/dx = 4 + 5x^(-2)

Then plugging this along with y = 4x - 5x^(-1) into the ODE given, and you should find it satisfies that equation.

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RideAnS [48]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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