Given: ∠A is a straight angle. ∠B is a straight angle.
We need to Prove: ∠A≅∠B.
We know straight angles are of measure 180°.
So, ∠A and <B both would be of 180°.
It is given that ∠A and ∠B are straight angles. This means that <u>both angles are of 180°</u> because of the <u>the definition of straight angles</u>. Using <u>the definition of equality</u>, m∠A=m∠B . Finally, ∠A≅∠B by <u>definition of congruent. </u>
The cost of 1 adult ticket in the off season is 42$, but it is asking for the child ticket's price so you would do 194-42 and you get 152. Then, you would divide 152/4 and you get 38 but this is during the off-season so you would double it and get 76.
The regular price for a child is 76$
But feel free to check my work :D
Answer: there are 10 multiple choice questions and 15 short-answer questions
Step-by-step explanation:
Let x represent the number of multiple choice questions in the test.
Let y represent the number of short-answer questions in the test.
If the test has 25 questions, it means that
x + y = 25
Multiple-choice questions are worth 2 points, and short-answer questions are worth 4 points. The test is worth a total of 80 points. It means that
2x + 4y = 80 - - - - - - - -1
Substituting x = 25 - y into equation 1, it becomes
2(25 - y) + 4y = 80
50 - 2y + 4y = 80
- 2y + 4y = 80 - 50
2y = 30
y = 30/2 = 15
x = 25 - y = 25 - 15 = 10
A. The number of multiple-choice questions plus the number of short-answer questions is 25.
I would say A
hope that helps!!!
Answer:
Kite
Step-by-step explanation:
To graph quadrilateral with points:
A(-1,-2)
B(5,1)
C(-3,1)
D(-1,4)
Thus, we graph the the given points and join the corners. The quadrilateral formed has the following features:
Measure of segment AB= Measure of segment BD = 6.708 units
Measure of segment AC= Measure of segment CD = 3.605 units
Thus, adjacent pair of sides of the quadrilateral are congruent.
Major diagonal BC cuts the minor diagonal AD at point E such that:
Measure of segment AE= Measure of segment ED = 3 units
m∠AEB = m∠DEB = 90°
Thus, major diagonal is a perpendicular bisector of the minor diagonal.
The above stated features fulfills the criterion of a kite.
Hence, the given quadrilateral ABCD is a kite.