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3 years ago

Find the energy required to lift 110 lb a distance of 35 ft.?

Mathematics

2 answers:

professor190 [17]3 years ago

8 0

The energy required is the product of force and distance. In foot-pounds, it is ...

... (110 lb) × (35 ft) = 3850 ft·lb

Nana76 [90]3 years ago

8 0

Answer:

Energy required = 3850 lb-ft.

Step-by-step explanation:

Since we know the formula of work done = Force × Displacement

Here work done is the energy to lift a weight to move it for a particular distance.

Now we know the value of weight and displacement both.

work done = 110×35 = 3850 lb-ft.

Therefore the energy required to displace a weight required energy will be = 3850 lb-feet

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AlekseyPX

Answer:

200 sq cm

Step-by-step explanation:

Lateral surface area is the surface area without the bases, or without the top and bottom. So, you just add up the area of the 4 sides.

The front and back are both 10 x 20, so 200 each = 400

The left and right are 5 x 20, so 100 each = 200

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2 years ago

What is the value of 8.4n - 3.2p when n=2 and p= 4

kramer

Answer:

Step-by-step explanation:

8.4(2) - 3.2(4)

16.8 - 12.8

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3 years ago

Find the GCF of the terms of the polynomial. 24x^5 + 32x^3 – 12x

FromTheMoon [43]

Answer:

$GCF_{Numerical}$ $= 4$ $GCF_{Variable}$ $= x$

Step-by-step explanation:

Lesson : GCF

Let us start on the numerical terms:

$24x^{5} + 32x^{3} - 12x$

$24 , 32,-12$

Common factors for all these numbers are 1 , 2 , and 4,

Since we are looking for GCF, 4 is the term for numerical GCF.

Now for the variable terms:

$x^{5} , x^{3} , x$

Common factors for all these numbers are x

Therefore x is the term for variable GCF

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3 years ago

Ben is 3 times as old as Daniel and is also 4 years older than daniel. how I'll is Daniel?

MatroZZZ [7]

If daniels age is x years we can create the equation:_

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2x = 4
x = 2

so Daniel is 2 years old

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3 years ago

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JKLM a kite, angle JKN=28° , and angle KLM=103° ". Find angle JML .

Ksju [112]

Answer:

Step-by-step explanation: 20

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3 years ago