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SCORPION-xisa [38]
3 years ago
6

Find the energy required to lift 110 lb a distance of 35 ft.?

Mathematics
2 answers:
professor190 [17]3 years ago
8 0

The energy required is the product of force and distance. In foot-pounds, it is ...

... (110 lb) × (35 ft) = 3850 ft·lb

Nana76 [90]3 years ago
8 0

Answer:

Energy required = 3850 lb-ft.

Step-by-step explanation:

Since we know the formula of work done = Force × Displacement

Here work done is the energy to lift a weight to move it for a particular distance.

Now we know the value of weight and displacement both.

work done = 110×35 = 3850 lb-ft.

Therefore the energy required to displace a weight required energy will be = 3850 lb-feet

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The lengths of a particular snake are approximately normally distributed with a given mean mu = 15 in. and standard deviation si
Helga [31]

The percentage of the snakes is longer than 16.6 in. with a mean of 15 in. and a standard deviation of 0.8 in. is 2.275%.

<h3>What is a normal distribution?</h3>

It is also called the Gaussian Distribution. It is the most important continuous probability distribution. The curve looks like a bell, so it is also called a bell curve.

The z-score is a numerical measurement used in statistics of the value's relationship to the mean of a group of values, measured in terms of standards from the mean.

The lengths of a particular snake are approximately normally distributed with a given mean = 15 in. and standard deviation = 0.8 in.

Then the percentage of the snakes is longer than 16.6 in. will be

z = \dfrac{ x - \mu }{ \sigma }\\\\z = \dfrac{16.6-15}{0.8}\\\\z = 2

Then we have

\rm P(x > 16.6) = P(z > 2) = 0.02275  \ or  \ 2.275 \%

More about the normal distribution link is given below.

brainly.com/question/12421652

6 0
2 years ago
What is the range of the equation
a_sh-v [17]

The range of the equation is y>2

Explanation:

The given equation is y=2(4)^{x+3}+2

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

y=2 \cdot 4^{x+3}+2

This can be written as y=2^{1+2(x+3)}+2

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

x=2^{1+2(y+3)}+2

Solving for y, we get;

x-2=2^{1+2(y+3)}

Applying the log rule, if f(x) = g(x) then \ln (f(x))=\ln (g(x)), then, we get;

\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)

Simplifying, we get;

(1+2(y+3)) \ln (2)=\ln (x-2)

Dividing both sides by \ln (2), we have;

2 y+7=\frac{\ln (x-2)}{\ln (2)}

Subtracting 7 from both sides of the equation, we have;

2 y=\frac{\ln (x-2)}{\ln (2)}-7

Dividing both sides by 2, we get;

y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}

Let us find the positive values for logs.

Thus, we have,;

x-2>0

     x>2

The function domain is x>2

By combining the intervals, the range becomes y>2

Hence, the range of the equation is y>2

7 0
4 years ago
A car travels 50 km in 2 liters find
Savatey [412]
It can travel 125km with 5 liters
And 6 liters to travel 150 :)
5 0
3 years ago
Read 2 more answers
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just olya [345]
I have no idea I’m doing the same thing rn but good luck bro bro
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3 years ago
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Find the surface area of the sphere with the given dimension. Leave your answer in terms of π. Sphere with radius of 60 m.
prohojiy [21]
The surface area of a sphere is given by A=4 \pi  r^{2} where r represents the radius.

As the radius is given as 60 meters we replace r with 60 in the formula above to get the surface area.

A=4 \pi ( 60^{2} )=14400 \pi
6 0
3 years ago
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