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3 years ago

What is the compliment of 41°

Mathematics

1 answer:

kozerog [31]3 years ago

3 0

Answer: 49°

Step-by-step explanation:

I'm guessing you meant complement? Complementary angles add up to 90°. 90° - 41° = 49°

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Please answer this correctly

HACTEHA [7]

The volume is approximately 50.27 cubic yards.

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3 years ago

What is the value of the 3 in 8.139

Fofino [41]

The 8 is in the ones place.

The 1 is in the tenths place.

The 3 is in the hundredths place.

The 9 is in the thousandths place.

hope it helps!

6 0

4 years ago

Use the formula for the difference of cubes to show that 125 - 27 = 98

IrinaVladis [17]

The formula is

a^3 - b^2 = (a - b)(a^2 + ab + b^2) so plugging in the given values:-

a = cube root of 125 = 5 and b = cube root of 27 = 3 , we get:-

125 - 27 = (5 - 3)(5^2 + 5*3 + 3^2)

= 2 * 49

= 98 answer

3 0

3 years ago

I just need help with this

lesya [120]

9.29 is your answer congrats

7 0

4 years ago

Read 2 more answers

Evaluate ∫C ysin(z)ds, where C is the circular helix given by the equations x = cos(t), y = sin(t), z = t, 0 ≤ t ≤ 2π. SOLUTION

Ivahew [28]

The line integral is

$\displaystyle\int_Cy\sin z\,\mathrm ds=\int_0^{2\pi}y(t)\sin z(t)\,\sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2+\left(\frac{\mathrm dz}{\mathrm dt}\right)^2}\,\mathrm dt$

We have

$x=\cos t\implies\dfrac{\mathrm dx}{\mathrm dt}=-\sin t$

$y=\sin t\implies\dfrac{\mathrm dy}{\mathrm dt}=\cos t$

$z=t\implies\dfrac{\mathrm dz}{\mathrm dt}=1$

so the integral reduces to

$\displaystyle\int_0^{2\pi}\sin^2t\sqrt{(-\sin t)^2+\cos^2t+1^2}\,\mathrm dt=\frac{\sqrt2}2\int_0^{2\pi}(1-\cos2t)\,\mathrm dt=\boxed{\frac\pi{\sqrt2}}$

5 0

4 years ago