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Sholpan [36]
3 years ago
7

What is the value of the 3 in 8.139

Mathematics
1 answer:
Fofino [41]3 years ago
6 0

The 8 is in the ones place.

The 1 is in the tenths place.

The 3 is in the hundredths place.

The 9 is in the thousandths place.

hope it helps!

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I need the anwser and the fractions
alexandr1967 [171]

Answer:

5.5/3 - 3/1 = 2.5/3

7 0
3 years ago
Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b
poizon [28]

The roots of the given polynomials exist  $x=8+\sqrt{10}$, and $x=8-\sqrt{10}$.

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\

$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\

$&x=8+\sqrt{10}, x=8-\sqrt{10}

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$, and

$x=8-\sqrt{10}$.

To learn more about quadratic equations refer to:

brainly.com/question/1214333

#SPJ4

3 0
1 year ago
Read 2 more answers
Can someone pleaseeee help me :(
dexar [7]

Answer: x-5 / x

Step-by-step explanation:

because…

4 0
2 years ago
Functions
Illusion [34]
I’m not sure but maybe true
3 0
3 years ago
How would I solve n/5-3n/10=1/5<br><br>pls help me I am literally failing math.
otez555 [7]

Answer:

53/5

Step-by-step explanation:

since 10 is the denominator of the denominator we can move it to the numerator, giving us 10n/5-3n = 1/5

multiply all sides by 5-3n, giving us 10n = (5-3n)/5

now multiply by 5 to get rid of the final denomintor, 50n = 5-3n

move 3n to the other side 53n = 5, n = 53/5

8 0
3 years ago
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