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anastassius [24]
3 years ago
12

What is the greatest common factor c^2d^2​

Mathematics
1 answer:
Brums [2.3K]3 years ago
8 0

Answer:

1

Step-by-step explanation:

Since there are no common prime factors, the only common factor for c²d² is 1, therfore it stays as is, c²d².

I am joyous to assist you anytime.

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Asdfghjkllkjhgfdsaas
natali 33 [55]

Answer:

13

Step-by-step explanation:

(x + 3)^3/2 = 64

√(x + 3)^3 = 64

(x + 3)^3 = 64^2

(x + 3)^3 = (4^3)^2

(x + 3)^3 = (4^2)^3

Same exponent

So

x + 3 = 4^2

x + 3 = 16

x = 13

6 0
3 years ago
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100 is 1/10 of what? <br> Someone please help
babunello [35]

Answer:

1000.  100x10=1000    100+100+100+100+100+100+100+100+100+100=1000

100/1000=1/10

Step-by-step explanation:

6 0
3 years ago
Consider f and c below. f(x, y) = x2 i + y2 j c is the arc of the parabola y = 2x2 from (−1, 2) to (1, 2) (a) find a function f
Korvikt [17]
If there is some scalar function f(x,y) such that

\nabla f(x,y)=\mathbf f(x,y)=x^2\,\mathbf i+y^2\,\mathbf j

then we want to find f such that

\dfrac{\partial f}{\partial x}=x^2\implies f(x,y)=\dfrac{x^3}3+g(y)
\dfrac{\partial f}{\partial y}=y^2=\dfrac{\mathrm dg}{\mathrm dy}\implies g(y)=\dfrac{y^3}3+C
\implies f(x,y)=\dfrac{x^3}3+\dfrac{y^3}3+C

So the vector field \mathbf f(x,y) is conservative, which means the fundamental theorem applies; the line integral of \mathbf f along any path \mathcal C parameterized by some vector-valued function \mathbf r(t) over a\le t\le b is given by

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=a}^{t=b}\mathbf f(\mathbf r(t))\cdot\dfrac{\mathrm d\mathbf r}{\mathrm dt}\,\mathrm dt=f(\mathbf r(b))-f(\mathbf r(a))

In this case,

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f(1,2)-f(-1,2)=\dfrac23
5 0
3 years ago
-5(k + 6) + 7(k – 4)
sergiy2304 [10]

Answer:

2k-58

Step-by-step explanation:

-5(k+6) + 7(k-4)

-5k-30+7k-28

2k-48

5 0
3 years ago
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never [62]
10x - (5+3x)
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