Lets factor first to see if we can make the problem simple
2(4x^2-25)
now we see that in parenthesis we have 2 square numbers
4x^2=(2x)^2
25=(5)^2
our expression is now
2(2x+5)(2x-5)
The equation of the line in point-slope form is given by:
Where,
(xo, yo): point that belongs to the line
m: slope of the line
The slope is given by:
Substituting values:
Rewriting:
Now we choose an ordered pair:
Substituting values we have:
We now rewrite the equation in its standard form:
Where,
b: cut with the y axis.
We have then:
Answer: point-slope form: or
standard form 
Answer:
When solving a multi step equation, you use PEMDAS (parentheses, exponents, multiplication, division, add, subtract), and you also use PEMDAS when solving a multi step inequality. However, inequalities are tricky in the fact that if you multiply or divide by a negative number, you must flip the sign. And while normally there are 1 or 2 solutions to a multi step equation, in the form of x= #, you'll have the same thing, but with an inequality sign (or signs).
A two-step equation is an algebraic equation that takes you two steps to solve. You've solved the equation when you get the variable by itself, with no numbers in front of it, on one side of the equal sign.
hope it helped
Explanation:
A sequence is a list of numbers.
A <em>geometric</em> sequence is a list of numbers such that the ratio of each number to the one before it is the same. The common ratio can be any non-zero value.
<u>Examples</u>
- 1, 2, 4, 8, ... common ratio is 2
- 27, 9, 3, 1, ... common ratio is 1/3
- 6, -24, 96, -384, ... common ratio is -4
___
<u>General Term</u>
Terms of a sequence are numbered starting with 1. We sometimes use the symbol a(n) or an to refer to the n-th term. The general term of a geometric sequence, a(n), can be described by the formula ...
a(n) = a(1)×r^(n-1) . . . . . n-th term of a geometric sequence
where a(1) is the first term, and r is the common ratio. The above example sequences have the formulas ...
- a(n) = 2^(n -1)
- a(n) = 27×(1/3)^(n -1)
- a(n) = 6×(-4)^(n -1)
You can see that these formulas are exponential in nature.
__
<u>Sum of Terms</u>
Another useful formula for geometric sequences is the formula for the sum of n terms.
S(n) = a(1)×(r^n -1)/(r -1) . . . . . sum of n terms of a geometric sequence
When |r| < 1, the sum converges as n approaches infinity. The infinite sum is ...
S = a(1)/(1-r)
