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Oksi-84 [34.3K]
2 years ago
15

While on vacation, Joan decides to rent a bike. When she picked up the bike, she paid half the fee, then paid her nephew $10 to

bring the bike back to the company store at the end of the day. How much money did Joan pay for the fee if all together, she spent $56 for the day?
Mathematics
1 answer:
nalin [4]2 years ago
6 0
$46 she paid her nephew $10 so you subtract that from the $56
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F divided by 28 equal 24
BabaBlast [244]
You can translate to:

F ÷ 28 = 24

F/28 = 24          Cross Multiply

F = 28 * 24

F = 672

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3 years ago
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miv72 [106K]

Answer:

I think it's A: Similar - AA

Step-by-step explanation:

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3 years ago
A drug company conducts trials of a new vaccine for a rare but usually fatal disease. The company creates a
GalinKa [24]

Answer:

What can be said about the model are;

1) The company predicts 4 failures before success

2) Each trial is independent

3) The probability is the same for each trial

4) Success is defined as preventing the disease

Step-by-step explanation:

The probability of success for the vaccine, p = 0.2

Therefore, the probability that the vaccine is effective and prevents the disease = 0.2

A geometric distribution probability of success is given by the following formula;

P(X = x) = p × q⁽ˣ⁻¹⁾

The expected value, E(Y) = 1/p

The number of failures before success, E(Y) = (1 - p)/p = (1 - 0.2)/0.2 = 4

Where;

q = The probability of a trial failing = 1 - p = 1 - 0.2 = 0.8

q = 1 - p

∴ The e

The geometric model criteria are;

a) Each trial can only have one of two outcomes success or failure

b) The probability of success for each trial is fixed

c) The geometric distribution is concerned with finding how many trials are required to get one success

d) The trials are independent

Therefore, we have;

The number of failures the company predicts before a success = 4 failures

2) The trials are independent

3) Each trial has an equal probability

4) Success is defined by the effectiveness of the vaccine in the prevention of the disease

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2 years ago
2.1 & 2.2 Assessment: Vertex & Standard Form of Quadratic Functions
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~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill

\begin{cases} h=1\\ k=-9 \end{cases}\implies y=a(x-1)^2 - 9\qquad \textit{we also know that} \begin{cases} x=2\\ y=-7 \end{cases} \\\\\\ -7=a(2-1)^2-9\implies 2=a(1)^2\implies 2=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill {\Large \begin{array}{llll} y=2(x-1)^2 -9 \end{array}} ~\hfill

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My name is Ann [436]
I believe that it is B
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