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pshichka [43]
3 years ago
8

Help me please I’m dumb

Mathematics
1 answer:
Snezhnost [94]3 years ago
6 0

The answer to this is D)

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A block of marble is in the shape of a rectangular prism. The block is 8 feet long, 2 feet wide, and 78 inches high. What is the
Komok [63]
Length of the block of marble in question is (l) = 8 feet
Width of the block of marble in question is (w) = 2 feet
Height of the block of marble in question is (h) = 78 inches
We already know that
1 inch = 0.08 foot
So
Height of the block of marble in question (h) = 78 * 0.08 foot
                                                                       = 6.24 feet
Then
Volume of the marble block = i * w * h
                                             = 8 * 2 * 6.24 cubic feet
                                             = 99.84 cubic feet
From the above dduction we can conclude that the volume of the marble block in the shape of a rectangular prism is 99.84 cubic feet.
7 0
3 years ago
The door on a model building is 10 inches tall. The door on the actual building is 4 yards tall. What was the scale used?
pychu [463]
The scale is 14.4 inches = 1 yard
3 0
3 years ago
Y=2x+0.5 I have to solve this using a weird table and then I have to graph it. How?
g100num [7]
You have to choose any input ,plug it in the equation ,solve it and look what is the output.Do that for the rest of the points . when you finish graph your points.
5 0
4 years ago
Please someone help me...​
Savatey [412]

use a^2-b^2=(a+b)(a-b)

to get (\cos^3A-\sin^3A)(\cos^3A+\sin^3A)

then use a^3+b^3=(a+b)(a^2+b^2-ab)

and a^3-b^3=(a-b)(a^2+b^2+ab)

also, \sin^2\theta+\cos^2\theta=1

to get (\cos A-\sin A)(1+\sin A\cos A)(\cos A+ \sin A)(1-\sin A\cos A)

then again use the first identity In both pairs, i.e.

(\cos A-\sin A)(\cos A+ \sin A) \cdot (1+\sin A\cos A)(1-\sin A\cos A)

to get \cos 2A (1-\sin^2A\cos^2A)

multiply and divide by 4 to get the RHS.

because, \sin(2A)= 2\sin A \cos A

squaring both sides, \sin^2 (2A)=4\sin^2A\cos^2A

3 0
3 years ago
Read 2 more answers
What additional information is obtained by measuring on an interval scale compared to an ordinal scale?
bulgar [2K]

Answer:

Step-by-step explanation:

From the given information.

An ordinal scale measurement does not give room to know the actual difference that coexists between the two measurements in a variable but in an interval scale of measurement, it is possible to deduce the actual difference that coexists between the two measurements in a variable.

Similarly, the ordinal scale only shows the rank of observations as per size and magnitude but in case of interval scale, it consists of classes with equal size, differentiated into direction and magnitude.

7 0
3 years ago
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