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atroni [7]
3 years ago
5

Mind giving me a hand?​

Mathematics
1 answer:
zaharov [31]3 years ago
7 0

Answer:

Jimmy has one candy times, 35 candies that his mom just gave him. He said, he's going togive 14 out of the 16 candies, he put a side to his mom

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a recycling bin is in the shape of a rectangular box find the height of the box if it's length is 18 ft its width is 8 feet and
OLEGan [10]
<h2>Answer:</h2>

The height of the box is:

                             4 ft.

<h2>Step-by-step explanation:</h2>

Let "h" denotes the height of the box.

Length of box is denoted by "l"

and breadth or width of box is denoted by "b"

We are given l=18 ft

b=8 ft.

Also we are given surface area of rectangular box= 496 ft²

As we know that the surface area of box is given by:

Surface\ Area=2(lb+bh+hl)

i.e.

496=2(18h+8h+144)\\\\i.e.\\\\\\496=2(26h+144)

Divide both side by 2.

248=144+26h\\\\i.e.\\\\26h=248-144\\\\i.e.\\\\26h=104

on dividing both side by 26 we get:

h=4

     Hence, the height of the  box is:

                    4 ft.

7 0
3 years ago
Read 2 more answers
Solve the equation: 1/2(x+4)=16-5(x+16)
eduard

Answer: -12

Step-by-step explanation:

7 0
3 years ago
The degree of the polynomial -5 + 3x^6 + 2x^5 + 6x^3 is
Lena [83]

Answer:

6

Step-by-step explanation:

As the highest power of x in the expression is 6, the degree is 6

8 0
3 years ago
Read 2 more answers
A rat is trapped in a maze. Initially he has to choose one of two directions. If he goes to the right, then he will wander aroun
Brut [27]

Answer:

The expected number of minutes the rat will be trapped in the maze is 21 minutes.

Step-by-step explanation:

The rat has two directions to leave the maze.

The probability of selecting any of the two directions is, \frac{1}{2}.

If the rat selects the right direction, the rat will return to the starting point after 3 minutes.

If the rat selects the left direction then the rat will leave the maze with probability \frac{1}{3} after 2 minutes. And with probability \frac{2}{3} the rat will return to the starting point after 5 minutes of wandering.

Let <em>X</em> = number of minutes the rat will be trapped in the maze.

Compute the expected value of <em>X</em> as follows:

E(X)=[(3+E(X)\times\frac{1}{2} ]+[2\times\frac{1}{6} ]+[(5+E(X)\times\frac{2}{6} ]\\E(X)=\frac{3}{2} +\frac{E(X)}{2}+\frac{1}{3}+\frac{5}{3} +\frac{E(X)}{3} \\E(X)-\frac{E(X)}{2}-\frac{E(X)}{3}=\frac{3}{2} +\frac{1}{3}+\frac{5}{3} \\\frac{6E(X)-3E(X)-2E(X)}{6}=\frac{9+2+10}{6}\\\frac{E(X)}{6}=\frac{21}{6}\\E(X)=21

Thus, the expected number of minutes the rat will be trapped in the maze is 21 minutes.

3 0
4 years ago
Hugo can run at a rate of 1/7 mile each minute how log will it take hime to run a 5 mile race
Vinil7 [7]
<span>35 minutes is your answer</span>
7 0
3 years ago
Read 2 more answers
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