It’d be 2. The same as the one on the opposite side
Step-by-step explanation:
the leading coefficient means the coefficient (factor) of the term with the highest exponent of the variable (typically x).
with sufficiently large values of this variable (x - going far enough to the right) this term will "win" in value against any other term of the polynomial expression.
and therefore the sign of its factor (coefficient) will determine, if the curve will go up or down.
a positive factor (coefficient) will make the value of this term and therefore of the whole polynomial larger and larger, making the curve going up to +infinity.
a negative factor (coefficient) will make the value of this term and therefore of the whole polynomial smaller and smaller (more negative and more negative), making the curve going down to -infinity.
Answer:
B. x≥-3
Step-by-step explanation:
To solve this problem, first you have to isolate it one one side of the equation.
First, multiply -1 from both sides.
(-9x)(-1)≥27(-1)
Solve.
27*-1=-27
9x≥-27
Next, divide by 9 from both sides.
9x/9≥-27/9
Then, solve.
-27/9=-3
Therefore, the correct answer is x≥-3.
No, 9/12 is equivalent to 3/4.
Hope this helps.
Answer: Choice B
a_n = 10(1/2)^(n-2) is the nth term
average rate of change = -35/3
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Explanation:
Each time x increases by 1, y is cut in half. For instance, going from (2,10) to (3,5) shows this.
If we want to go in reverse, decreasing x by 1 will double the y value. So (1,20) is another point and (0,40) is another. We'll be using (0,40) and (3,5) because we want the average rate of change from x = 0 to x = 3. I'm using x in place of n here.
Use the slope formula to find the slope of the line through (0,40) and (3,5)
m = (y2-y1)/(x2-x1)
m = (5-40)/(3-0)
m = -35/3
The negative slope means the line goes downhill as you read it from left to right. The average rate of change from n = 0 to n = 3 is -35/3
The nth term of this geometric sequence is 20(1/2)^(n-1) since 20 is the first term (corresponds to n = 1) and 1/2 is the common ratio. Your teacher has done a bit of algebraic manipulation to change the n-1 into n-2. This means the 20 has to change to 10 to counterbalance.
In other words, 20(1/2)^(n-1) is equivalent to 10(1/2)^(n-2) when n starts at n = 1.
