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Oksi-84 [34.3K]
3 years ago
7

What is the length , in units , of line segment A'C'?

Mathematics
1 answer:
Alex17521 [72]3 years ago
7 0
With rotation, the values of the triangle won't change. So, A'C' is the same as AC. Good luck afterwards
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11. Any company plans to connect a total of 20 pF of capacitance to a 7200-V
vesna_86 [32]

Answer:

C = 80pF

Step-by-step explanation:

The total capacitance of 4 capacitors connected in series is given by:

Ct = \frac{1}{1/C1 + /C2 + 1/C3 + 1/C4}

Ct = \frac{1}{1/C + /C + 1/C + 1/C}

Ct = \frac{1}{4/C}

Ct = \frac{C}{4}=20pF

Solving for C:

C = 4*20pF

C = 80pF

3 0
3 years ago
Use the Factor Theorem to find ALL zeros of f(x) = x^3 - x^2 - 11x + 15, given that 3 is a zero. Show all work and express zeros
ELEN [110]

Answer:

Step-by-step explanation:

by synthetic division

3) 1   -1   -11    15

|       3     6   -15   (add)

____________

   1     2    -5 |0

x²+2x-5=0

x=\frac{-2 \pm\sqrt{2^{2} -4*1*-5} }{2*1} \\or~x=\frac{-2 \pm\sqrt{4+20} }{2} \\or~x=\frac{-2 \pm2\sqrt{6} }{2} \\or ~x=-1 \pm \sqrt{6}

5 0
3 years ago
NEED HELP! will give brainiest!!
Flura [38]

Answer: 62999

Step-by-step explanation: sorry if wrong

3 0
2 years ago
Expand and simplify (3x+5)(4x-1)
Whitepunk [10]
Use FOIL and simply, First times First, Outside times Outside, Inside times Inside, Last times Last.

(3x+5)(4x-1)
3x * 4x = 12x²
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5 * -1 = -5

12x² - 3x + 20x - 5

Now simplify by adding -3x to 20x and get:

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5 0
3 years ago
The local public transport authority is conducting research into commuter behaviour. A previous census indicated that the mean c
kondor19780726 [428]

Answer:

H_0:\mu  = 45 and H_a:\mu  < 45

T = 34.88

The null hypothesis is not rejected

Step-by-step explanation:

Given

Random sample of 50 commuter times

Solving (a): The null and alternate hypothesis

From the question, a previous census shows that:

\mu =45 and \sigma= 9.1

This is the null hypothesis i.e.

H_0:\mu  = 45

Reading further, a new test was to show whether the average has decreased.

This is the alternate hypothesis, and it is represented as:

H_a:\mu  < 45

Solving (b) and (c): The test statistic (T).

This is calculated using:

T = \frac{\mu}{\sigma/\sqrt n}

In this case:

n = 50   \mu =45 and \sigma= 9.1

So:

T = \frac{45}{9.1/\sqrt{50}}

T = \frac{45}{9.1/7.07}

T = \frac{45}{1.29}

T = 34.88

Solving (c): Accept or reject null hypothesis

\alpha = 0.05

First calculate the degrees of freedom (df)

df = n - 1 = 50 - 1

d f = 49

From the t distribution table,

At: d f = 49,  \alpha = 0.05 and T = 34.88

the t score is:

p = 1.676

p > 0.05

<em>So, the null hypothesis is not rejected</em>

7 0
3 years ago
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