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3 years ago

Please answer????? Need help

Mathematics

2 answers:

cestrela7 [59]3 years ago

5 0

Message me the question and I will help you, your image isnt showing up on my computer

Sindrei [870]3 years ago

4 0

I attached a picture, in the picture it shows you how to do the problem.

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If <img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20x" id="TexFormula1" title="f(x) = x" alt="f(x) = x" align="absmiddle" clas

Paraphin [41]

Answer:

Remainder is 93

Step-by-step explanation:

Use synthetic division:

-9 | 1 -1 3

____<u> -9 90</u>

1 -10 | 93

Therefore, the remainder is 93

7 0

3 years ago

Tyra wants to arrange 32 tiles in equal rows and columns. How many ways could she organaize the tiles. List the factors.

bogdanovich [222]

2 ways

4 rows 8 columns

8 rows 4 columns

5 0

4 years ago

How many pepperoni pizzas did they buy if they bought 6 cheese pizzas

Alla [95]

Answer:

Question is incomplete but use below

Step-by-step explanation:

you can do total = (price of cheese pizza) ( amount of cheese pizzas bought)+(price of pepperoni pizza) ( amount of pepperoni pizzas bought)

5 0

3 years ago

Read 2 more answers

Assume the heights in a female population are normally distributed with mean 65.7 inches and standard deviation 3.2 inches. Then

maria [59]

Answer:

Choice a. approximately $0.62$ .

Step-by-step explanation:

This explanation shows how to solve this problem using a typical $z$ -score table. Consider a normal distribution with mean $\mu$ and variance $\sigma^2$ . The $z\!$ -score for a measurement of value $x$ would be $(x - \mu) / \sigma$ .

Convert all heights to inches:

$5\; \rm ft = 5 \times 12 \; in = 60\; \rm in$ .
$5\; \rm ft + 7\; \rm in = 5 \times 12 \; in + 7\; \rm in = 67\; \rm in$ .

Let $X$ represent the height (in inches) of a female from this population. By the assumptions in this question: $X \sim \mathrm{N}(65.7,\, 3.2)$ . The question is asking for the probability $P(60 \le X \le 67)$ . Calculate the $z$ score for the two boundary values:

For the lower bound, $60\; \rm in$ : $\displaystyle z = \frac{60 - 65.7}{3.2} \approx -1.78$ .
For the upper bound, $67\; \rm in$ : $\displaystyle z = \frac{67 - 65.7}{3.2} \approx 0.41$ .

Look up the corresponding probabilities on a typical $z$ -score table.

For the $z$ -score of the upper bound, the corresponding probability is approximately $0.6591$ . In other words:

$P(x \le 67) \approx 0.6591$

On the other hand, some $z$ -score table might not include the probability for negative $z\!$ scores. That missing part can be found using the symmetry of the normal distribution PDF.

The probability corresponding to $P(z < 1.78)$ (that's the opposite of the $z\!$ -score at the lower bound) is approximately $0.9625$ . By the symmetry of the normal PDF: