If P(E) = 0.25, what are the odds against E?

For each equation, decide if it is always true or never true. x − 13 = x + 1 x + 1 2 = x − 1 2 2 ( x + 3 ) = 5 x + 6 − 3 x x − 3

mrs_skeptik [129]

"x" (and any subsequent words) was ignored because we limit queries to 32 words.

6 0

1 year ago

Help please due soon

HACTEHA [7]

Answer:

i think it's 15%

Step-by-step explanation:

6 0

2 years ago

A local hamburger shop sold a combined total of 712 hamburgers and cheeseburgers on Tuesday. There were 62 more cheeseburgers so

hammer [34]

A local hamburger shop sold a total of 712 burgers on Tuesday

There are 62 more cheeseburgers than hamburgers

let cheeseburers = c
let hamburgers = h

h + 62 = c
c + h = 712

Plug in h + 62 for c

(h + 62) + h = 712
2h + 62 = 712
2h + 62 (-62) = 712 (-62)
2h = 650
2h/2 = 650/2
h = 325

There are 325 hamburgers sold on Tuesday

c = 325 + 62
c = 387

There are 387 chesseburgers sold on tuesday (in case you were wondering)

hope this helps

4 0

2 years ago

How do you put 943,261,586 with base ten numbers

Citrus2011 [14]

Answer:

(9 $\times$ $10^{8}$ ) + (4 $\times$ $10^{7}$ ) + (3 $\times$ $10^{6}$ ) + (2 $\times$ $10^{5}$ ) + (6 $\times$ $10^{4}$ ) + ( $10^{3}$ ) + (5 $\times$ $10^{2}$ ) + (8 $\times$ 10) + (6 $\times$ $10^{0}$ )

Step-by-step explanation:

How do you put 943,261,586 with base ten numbers

943,261,586 =

900,000,000 + 40,000,000 + 3,000,000 + 200,000 + 60,000 + 1,000 + 500 + 80 +6 =

(9 $\times$ $10^{8}$ ) + (4 $\times$ $10^{7}$ ) + (3 $\times$ $10^{6}$ ) + (2 $\times$ $10^{5}$ ) + (6 $\times$ $10^{4}$ ) + ( $10^{3}$ ) + (5 $\times$ $10^{2}$ ) + (8 $\times$ 10) + (6 $\times$ $10^{0}$ )