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mestny [16]
3 years ago
6

Farmer Ed has 1.000 meters of​ fencing, and wants to enclose a rectangular plot that borders on a river. If Farmer Ed does not f

ence the side along the​ river, what is the largest area that can be​ enclosed?
Mathematics
1 answer:
Lady_Fox [76]3 years ago
7 0

Answer:

  1000 m of fence can make a 3-sided enclosure of 125,000 m²

Step-by-step explanation:

Let x represent the length of fence parallel to the river. Then the perpendicular dimension is ...

  width = (1000 -x)/2

and the enclosed area is ...

  area = length×width = (x)(1000 -x)/2

This describes a downward-opening parabola with zeros at x=0 and x=1000. The vertex (maximum) is halfway between, at x=500.

Then the maximum area is ...

  area = (500)(1000 -500)/2 = 125,000 . . . . square meters

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Lakeview is 101 miles from Springfield. Irania must go to the law library in Springfield to get a document for the law firm for
Arlecino [84]

Answer: Approximately 4.1224 hours

4.1224 hours = 4 hours, 7 minutes, 21 seconds approximately

===========================================

Work Shown:

d = distance = 2*101 = 202 miles

r = rate or speed = 49 mph

t = time = unknown

d = r*t

202 = 49*t

49t = 202

t = 202/49

t = 4.1224 hours approximately

--------------

If you want to convert to hours,minutes,seconds, then...

4.1224 hours = 4 hours + 0.1224 hours

4.1224 hours = 4 hours + (0.1224*60) min

4.1224 hours = 4 hours + 7.344 min

4.1224 hours = 4 hours + 7 min + 0.344 min

4.1224 hours = 4 hours + 7 min + (0.344*60) sec

4.1224 hours = 4 hours + 7 min + 20.64 sec

4.1224 hours = 4 hours + 7 min + 21 sec ..... approximate

4.1224 hours = 4 hours, 7 min, 21 sec .... also approximate

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4 0
3 years ago
X=1-2y how would you solve this?
Ivahew [28]

Answer:

You can't have a single answer.

Step-by-step explanation:

An indiviual equation can't be solved if it has 2 variables.

You can, however, graph it.

The line will create all the possible sets of answers for the problem.

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