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mestny [16]
3 years ago
6

Farmer Ed has 1.000 meters of​ fencing, and wants to enclose a rectangular plot that borders on a river. If Farmer Ed does not f

ence the side along the​ river, what is the largest area that can be​ enclosed?
Mathematics
1 answer:
Lady_Fox [76]3 years ago
7 0

Answer:

  1000 m of fence can make a 3-sided enclosure of 125,000 m²

Step-by-step explanation:

Let x represent the length of fence parallel to the river. Then the perpendicular dimension is ...

  width = (1000 -x)/2

and the enclosed area is ...

  area = length×width = (x)(1000 -x)/2

This describes a downward-opening parabola with zeros at x=0 and x=1000. The vertex (maximum) is halfway between, at x=500.

Then the maximum area is ...

  area = (500)(1000 -500)/2 = 125,000 . . . . square meters

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Find the surface area of the figure.<br> PLEASE HELP!
olya-2409 [2.1K]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
Solve the proportion
mario62 [17]

Answer:

\boxed{\sf x = 5}

Step-by-step explanation:

\sf Solve  \: for  \: x  \: over  \: the  \: real \:  numbers:  \\ \sf \implies  \frac{2}{x - 3}   =  \frac{5}{x}  \\  \\  \sf Take  \: the \:  reciprocal  \: of  \: both \:  sides:  \\ \sf \implies  \frac{x - 3}{2}  =  \frac{x}{5}  \\  \\  \sf Expand  \: out \:  terms \:  of \:  the \:  left  \: hand \:  side:  \\  \\ \sf \implies \frac{x}{2}  -  \frac{3}{2}  =  \frac{x}{5}  \\  \\  \sf Subtract \:  \frac{x}{5}   -  \frac{3}{2}  \: from  \: both  \: sides: \\  \sf \implies \frac{x}{2}  -  \frac{3}{2} - ( \frac{x}{5}   -  \frac{3}{2} ) =  \frac{x}{5} - ( \frac{x}{5}  -  \frac{3}{2} ) \\  \\  \sf \implies \frac{x}{2}  -  \frac{3}{2} -  \frac{x}{5}    +   \frac{3}{2} =  \frac{x}{5} -  \frac{x}{5}  +  \frac{3}{2}  \\  \\  \sf \frac{x}{5}  -  \frac{x}{5}  = 0 :  \\  \sf \implies \frac{x}{2}  -  \frac{x}{5}  -  \frac{3}{2}  +  \frac{3}{2}  =  \frac{3}{2}  \\  \\  \sf  \frac{3}{2}   -   \frac{3}{2}   = 0:  \\  \sf \implies \frac{x}{2}  -  \frac{x}{5}  =  \frac{3}{2}   \\  \\ \sf \frac{x}{2}  -  \frac{x}{5} =  \frac{5x - 2x}{10}  =  \frac{3x}{10} :  \\   \sf \implies \frac{3x}{10}  =  \frac{3}{2}   \\  \\ \sf Multiply \:  both  \: sides \:  by \:  \frac{10}{3}  : \\   \sf \implies \frac{3x}{10}  \times  \frac{10}{3}  =  \frac{3}{2 }  \times  \frac{10}{3}   \\  \\ \sf \frac{3x}{10}  \times  \frac{10}{3}  =   \cancel{\frac{3}{10} } \times( x) \times  \cancel{ \frac{10}{3} } = x :  \\  \sf \implies x =  \frac{3}{2}  \times  \frac{10}{3} \\  \\   \sf  \frac{3}{2}  \times  \frac{10}{3}  = \cancel{ \frac{3}{2} }  \times \cancel{ \frac{3}{2} }  \times 5 :   \\ \sf \implies x = 5

8 0
3 years ago
Please help me with this question!!!!!​
Naddika [18.5K]

Answer:

Equation of line in slope-intercept form that passes through (4, -8) and is perpendicular to the graph y= \frac {2}{5} x - 3 is below

y = - \frac {5}{2} x + 2

Step-by-step explanation:

Slope of the equation  y= \frac{2}{5} x -3   is  m_1 = \frac{2}{5}

Since slopes of perpendicular lines are negative reciprocal of each other, therefore slope of other line is given as

m_2 = - \frac {1}{m_1}  = - \frac {5}{2}

Equation of line in point slope form is given as

y-y_1=m_2(x-x_1)

Here  (x1, y1) = (4, -8)

y+8 = - \frac{5}{2} (x-4)

Simplifying it further  

y = - \frac {5}{2} x + \frac {5}{2} 4 - 8

y = - \frac {5}{2} x + 2

6 0
3 years ago
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