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mestny [16]
3 years ago
6

Farmer Ed has 1.000 meters of​ fencing, and wants to enclose a rectangular plot that borders on a river. If Farmer Ed does not f

ence the side along the​ river, what is the largest area that can be​ enclosed?
Mathematics
1 answer:
Lady_Fox [76]3 years ago
7 0

Answer:

  1000 m of fence can make a 3-sided enclosure of 125,000 m²

Step-by-step explanation:

Let x represent the length of fence parallel to the river. Then the perpendicular dimension is ...

  width = (1000 -x)/2

and the enclosed area is ...

  area = length×width = (x)(1000 -x)/2

This describes a downward-opening parabola with zeros at x=0 and x=1000. The vertex (maximum) is halfway between, at x=500.

Then the maximum area is ...

  area = (500)(1000 -500)/2 = 125,000 . . . . square meters

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Assume the resting heart rates for a sample of individuals are normally distributed with a mean of 75 and a standard deviation o
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Answer:

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b) 0.16

c) 0.475

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 75

Standard deviation = 5

We also have that since the normal distribution is symmetric, 50% of the measures are below the mean and 50% are above.

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So all the 50% below the mean is below 85

And of the 50% above the mean, 95% is less than 85. So

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b. The relative frequency of rates greater than 80 using the 68-95-99.7 rule is

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Of the 50% above the mean, 68% is less than 80. So 100-68 = 32% is more than 80.

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So 95% of 50%

0.95*0.5 = 0.475

6 0
4 years ago
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