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3 years ago

Give the opposite of each number. a. 3 b. –9 c. –5 d. 12

Mathematics

2 answers:

frez [133]3 years ago

6 0

The answer is: -3, 9, 5, -12. Hope this helps! Have a nice day!

inessss [21]3 years ago

5 0

Opposites:
a. -3
b. 9
c. 5
d. -12

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Two trains leave stations 456 miles apart at the same time and travel toward each other. One train travels at 105 miles per hour

love history [14]

Answer:

let x=distance 105 mph train traveled

(456-x)=distance 85 mph train traveled

Travel time = distance/speed (equal in both directions)

x/105=(456-x)/85

85x=105*456-105x

190x=105*456

x=105*456/190=252 miles

travel time=252/105=2.4 hrs

ans:

The two trains will meet in 2.4 hrs

Step-by-step explanation:

there brainliest pls

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3 years ago

A squirrel runs at a steady rate of 0.51 m/s in a circular path around a tree. If the squirrel's centripetal acceleration is 0.4

exis [7]

The image is answer.................

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3 years ago

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You want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable estimate for the

Vesna [10]

Answer:

A sample size of at least 1,353,733 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a pvalue of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

You would like to be 98% confident that you esimate is within 0.1% of the true population proportion. How large of a sample size is required?

We need a sample size of at least n.

n is found when M = 0.001.

Since we don't have an estimate for the proportion, we use the worst case scenario, that is $\pi = 0.5$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.001 = 2.327\sqrt{\frac{0.5*0.5}{n}}$

$0.001\sqrt{n} = 2.327*0.5$

$\sqrt{n} = \frac{2.327*0.5}{0.001}$

$(\sqrt{n})^{2} = (\frac{2.327*0.5}{0.001})^{2}$

$n = 1353732.25$

Rounding up

A sample size of at least 1,353,733 is required.

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3 years ago

Use the functions h(x) = 2x − 5 and t(x) = 6x + 4 to complete the function operations listed below.

Anika [276]

For this case we have the following functions:
h (x) = 2x - 5
t (x) = 6x + 4

Part A: (h + t) (x)
(h + t) (x) = h (x) + t (x)
(h + t) (x) = (2x - 5) + (6x + 4)
(h + t) (x) = 8x - 1

Part B: (h ⋅ t) (x)
(h ⋅ t) (x) = h (x) * t (x)
(h ⋅ t) (x) = (2x - 5) * (6x + 4)
(h ⋅ t) (x) = 12x ^ 2 + 8x - 30x - 20
(h ⋅ t) (x) = 12x ^ 2 - 22x - 20

Part C: h [t (x)]
h [t (x)] = 2 (6x + 4) - 5
h [t (x)] = 12x + 8 - 5
h [t (x)] = 12x + 3

6 0

3 years ago

Factor 64 – x15. (4 – x3)(16 + 4x3 + x3) (4 – x3)(16 + 4x3 + x6) (4 – x5)(16 + 4x5 + x5) (4 – x5)(16 + 4x5 + x10)

Dimas [21]

(4-x^5) (16+4x^5+x^10)
I hope this helps!

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3 years ago

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