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3 years ago

Give the opposite of each number. a. 3 b. –9 c. –5 d. 12

Mathematics

2 answers:

frez [133]3 years ago

6 0

The answer is: -3, 9, 5, -12. Hope this helps! Have a nice day!

inessss [21]3 years ago

5 0

Opposites:
a. -3
b. 9
c. 5
d. -12

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What is the solution set for the given inequality if the replacement set for r is {5, 6, 7, 8, 9, 10}? 2r ≤ 3r – 8 A. {8, 9, 10}

TiliK225 [7]

$2r\leq3r-8\\
r\geq8\\\Downarrow\\
\boxed{\{8,9,10\}}$

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3 years ago

The square root of 52 is between which two consecutive Integers?

Murrr4er [49]

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3 years ago

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Pavel [41]

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4 years ago

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Assoli18 [71]

Answer: $6\sqrt{3}$

======================================================

Explanation:

Method 1

We can use the pythagorean theorem to find x.

$a^2+b^2 = c^2\\\\6^2+x^2 = 12^2\\\\36+x^2 = 144\\\\x^2 = 144-36\\\\x^2 = 108\\\\x = \sqrt{108}\\\\x = \sqrt{36*3}\\\\x = \sqrt{36}*\sqrt{3}\\\\x = 6\sqrt{3}\\\\$

-----------------------------------

Method 2

Use the sine ratio to find x. You'll need a reference sheet or the unit circle, or simply memorize that sin(60) = sqrt(3)/2

$\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(60^{\circ}) = \frac{x}{12}\\\\\frac{\sqrt{3}}{2} = \frac{x}{12}\\\\x = 12*\frac{\sqrt{3}}{2}\\\\x = 6\sqrt{3}\\\\$

-----------------------------------

Method 3

Similar to the previous method, but we'll use tangent this time.

Use a reference sheet, unit circle, or memorize that tan(60) = sqrt(3)

$\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(60^{\circ}) = \frac{x}{6}\\\\\sqrt{3} = \frac{x}{6}\\\\x = 6\sqrt{3}\\\\$

-----------------------------------

Method 4

This is a 30-60-90 triangle. In other words, the angles are 30 degrees, 60 degrees, and 90 degrees.

Because of this special type of triangle, we know that the long leg is exactly sqrt(3) times that of the short leg.

$\text{long leg} = (\text{short leg})*\sqrt{3}\\\\x = 6\sqrt{3}\\\\$

The short leg is always opposite the smallest angle (30 degrees).

3 0

2 years ago

What is the value of the expression if m = –5 and n = 3? Negative StartFraction 24 Over 25 EndFraction Negative StartFraction 4

KatRina [158]

You can use the fact that a number raised to negative powers can be written as 1 divided by that number raised to positive number.

The value of the given expression when m = -5 and n= 3 is $-\dfrac{2}{5}$

<h3>How can we rewrite a number raised to negative power?</h3>

Suppose we've got $a^{-b}$ . then it can be rewritten as

$a^{-b} = \dfrac{1}{a^b}$

It is because $a^0 = 1$ for any a except 0, and that $\dfrac{a^0}{a^b} = a^{0-b} = a^{-b}$

If base are same and there is multiplication, then there will be addition in power.

Also, know the fact that if base are same and there is division, there will be subtraction in power(subtracting since that denominator when goes up, its power gets negated(gets negative sign to the existing power)

Thus,

$a^b \timesa ^c = a^{b+c}\\\\\dfrac{a^b}{a^c} = a^{b-c}$

<h3>Using above method to simplify the given expression before evaluating</h3>

The given expression is $\dfrac{2m^{-1}n^5}{3m^0n^4} = \dfrac{2n^5}{3m^0m^1n^4} = \dfrac{2n^5}{3mn^4} = \dfrac{2n^{5-4}}{3m} = \dfrac{2n^1}{3m} = \dfrac{2n}{3m}$

Putting m = -5 and n=3, we get:

$\dfrac{2\times 3}{3 \times -5} = -\dfrac{2}{5}$

Thus,

The value of the given expression when m = -5 and n= 3 is $-\dfrac{2}{5}$

Learn more about base and exponent(power) here:

brainly.com/question/847241

4 0

3 years ago