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2 years ago

3x+y+z=4 2x+2y+3z=3 X+3y+2z=5

1 answer:

6 0

1) 3x+y+z=4
2) 2x+2y+3z=3
3) x+3y+2z = 5

1)*2 6x + 2y + 2z = 8
2) 2x + 2y +3z = 3
- __________________
4x - z = 5

2)*3 6x + 6y + 9z = 9
3)*2 2x + 6y + 4z = 10
- __________________
4x+5z =-1

4x+5z = -1
4x - z =5
- ________
6z = -6
z = -1

If z=-1,

4x -(-1) =5
4x = 5-1
x = 4/4
x=1

3x+y+z=4
3(1)+y+(-1)=4
3+y-1=4
y=2

So z=-1, x=1, y=2

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Mars2501 [29]

Answer:

Point O is the center of the circle.

Part (a)

$\overline{A\:\!F}$ is a chord.

$\overline{OD}$ is a segment of the radius and is perpendicular to $\overline{A\:\!F}$

If a radius is perpendicular to a chord, it bisects the chord (divides the chord into two equal parts).

Therefore, $\overline{AD}=\overline{DF}$

Part (b)

If $\overline{BE}$ was extended past point E to touch the circumference it would be a chord.

As $\overline{OC}$ is perpendicular to $\overline{BE}$ , it would bisect the chord, but as $\overline{BE}$ is only a portion of a chord, $\overline{OC}$ does not bisect $\overline{BE}$ .

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1 year ago

Kite WXYZ is graphed on a coordinate plane. What is the approximate perimeter of the kite? Round to the nearest tenth. 10.6 unit

Archy [21]

Answer-

Perimeter of the kite is 16.2 units

Solution-

As WXYZ is a kite, so two disjoint pairs of consecutive sides are congruent, i.e WX=XY and WZ=ZY

So, perimeter of the kite WXYZ is,

$=2(\overline{WX}+\overline{WZ})$

And

$\overline{WX}=\sqrt{(1-3)^2+(1-4)^2}=\sqrt{(-2)^2+(-3)^2}=\sqrt{4+9}=\sqrt{13}$

$\overline{WZ}=\sqrt{(1-3)^2+(1+3)^2}=\sqrt{(-2)^2+(4)^2}=\sqrt{4+16}=\sqrt{20}$

So, perimeter will be,

$P=2(\sqrt{13}+\sqrt{20})=16.15\approx 16.2\ units$

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2 years ago

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Answer:

Step-by-step explanation:

False

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2 years ago

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Answer:

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Step-by-step explanation:

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