You can either use the Pythagorean theorem right away (a = -3, b = 27, c = 1200) or Try factoring the polynomial to find the zeros.
I would factor and start by dividing everything by -3.
<span>-3x^4 + 27x^2 + 1200 = 0
-3(x^4 - 9x^2 - 400) = 0
If you divide by -3 on both sides you see that the -3 is now gone. 0/-3 = 0
x^4 - 9x^2 - 400 = 0
factor further or use Pythagorean theorem.
(x² - 25)(x² + 16) = 0
Solve for the x-values by setting each one equal to zero.
x² - 25 = 0
x² = 25
x is +5 or -5
x² + 16 = 0
x² = -16
x = √(-16)
Two non-real solutions
x is +4i or -4i
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There are numerous ways you can do this, but take a look at the attachment to see how I did it. I hope it answers your question! :)
Answer:
300m
Step-by-step explanation:
- Because d = rt
- 20 * 15 = 300
Answer:
D) y = -2
The equation of the perpendicular line to the given line is y = -2
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given point (-3,-2)
In graph the equation of line x = 8 ( parallel to y- axis )
1 x + o y - 8 =0
The equation of the perpendicular line to the given line
b x - a y + k =0
o x - 1 y + k =0 ...(i)
The equation (i) is Paases through the point ( -3,-2)
0 ( -3) -1(-2) + k =0
2 + k =0
k = -2
∴<em>The equation of the perpendicular line to the given line is </em>
<em> put k = -2 in equation (i) </em>
o x - 1 y + k =0
- y +(-2) =0
- y = 2
y = -2
<u><em>Final answer:-</em></u>
∴The equation of the perpendicular line to the given line is y =-2
