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slava [35]
3 years ago
5

PLZZ I NEED THIS FAST!

Mathematics
2 answers:
Travka [436]3 years ago
7 0

For those just looking for the answer: D

The answer is D- 14 × (2 + 5), as 14 x 2 is 28 and 14 x 5 is 70. 2 and 5 are prime numbers with no common factors, so they can't be further simplified.

Burka [1]3 years ago
5 0

So remember that GCFs are greatest common factors, or the greatest number and/or variable that divides 2 or more terms nicely (aka no decimals).

With this, you at least know that a factor of these two numbers is 7, which turns this expression to 7(4 + 10). However, what's inside the parentheses can still be factored out with a GCF of 2. So you can further factor the expression as 2 * 7(2 + 5), which can be simplified to 14(2 + 5), or D. Since 2 and 5 do not have GCFs greater than 1, that is your answer.

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The sum of -7.68 and it’s additive inverse is??
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raketka [301]
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work for a publishing company. The company wants to send two employees to a statistics conference. To be​ fair, the company deci
NISA [10]

Answer:

Step-by-step explanation:

Here is the complete question.

Dominique, Marco, Roberto , and John work for a publishing company. The company wants to send two employees to a statistics conference. To be fair, the company decides that the two individuals who get to attend will have their names drawn from a hat. This is like obtaining a simple random sample of size 2. (a) Determine the sample space of the experiment. That is, list all possible simple random samples of size n = 2. (b) What is the probability that Dominique and Marco attend the conference? (c) What is the probability that John attends the conference?  ​(d) What is the probability that John stays​ home?

Since there are four employees to select the two to send from. then for us to get the sample space for the experiment we need to merge all possible two employees and represent them as set.

Let D = Dominique, M = Marco, R = Roberto and J = John

a) The sample space for the experiment is the total number of possible outcomes that we can have. It is as given below

S = 4C2 = 4!/(4-2)!2! (Selecting 2 out of 4 employees)

Total sample space = 4!/2!2!

Total sample space = 4*3*2!/2!2

Total sample space = 12/2 = 6

The sample space are S = {DM, DR, DJ, MR, MJ, RJ}

b) Probability is the ratio of number of event to the sample space.

P = n(E)/n(S)

Given n(S) = 6

n(E) is the event of Dominique and Marco attending the conference.

E = {DM}

n(E) = 1

P(D and M) = 1/6

Hence  the probability that Dominique and Marco attend the conference is 1/6

c) For John to attend the conference, the event outcome will be given as;

E = {DJ, MJ, RJ}

n(E) = 3

n(S) = 6

Probability for John to attend the conference is 3/6 = 1/2

d) Probability that John stays at home = 1 - Prob (John attends the conference)

Probability that John stays at home = 1 - 1/2

Probability that John stays at home = 1/2

7 0
3 years ago
What are 3 odd consecutive integers with the sum of 3639 and what are 3 consecutive even integers with a sum of 672
Tju [1.3M]
X+(x+2)+(x+4)=3639
3x+6=3639
3x=3633
X=1211
Numbers are: 1211, 1213, 1215

X+(x+2)+(x+4)=672
3x+6=672
3x=666
X=222
Numbers are: 222,224,226
8 0
2 years ago
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