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cluponka [151]
3 years ago
5

Please help!

Mathematics
1 answer:
Ivenika [448]3 years ago
3 0

<u>SOLUTION TO QUESTION 1</u>

For v-6\ge4


We add 6 to both sides of the inequality. This gives us


v-6+6\ge4+6


We simplify to obtain;


v+0\ge10


Hence,

v\ge 10

See the attachment for graph.


<u>SOLUTION TO QUESTION 2</u>


For the inequality -5x


We divide both sides by -5 and reverse the inequality sign because, we are dividing by a negative number. This implies that;


\frac{-5x}{-5}> \frac{15}{-5}


We simplify to get,

x>-3


See attachment for graph


<u>SOLUTION TO QUESTION 3</u>


For 3k>5k+12

We group the terms in k on the left hand side of the inequality,

3k-5k>12


We simplify to obtain;


-2k>12


We divide both sides by -2 and reverse the inequality sign because, we are dividing by a negative number again. This implies that;


\frac{-2k}{-2}


This simplifies to;


k

See attachment for graph.


<u>SOLUTION TO QUESTION 4</u>

Given the set {5,10,15}

All the possible subsets are;

{}, {5}, {10}, {15}, {5,10}, {5,15}, {10,15}, and {5,10,15}



<u>SOLUTION TO QUESTION 5</u>

For 2t\le-4 \: or\:7t\ge 49

We divide through the first inequality by 2 and the second inequality by 7 to obtain;


t\le-2 \: or\: t\ge 7

Or

t\le-2 , t\ge 7



<u>SOLUTION TO QUESTION 6</u>

We have |n+2|=4

This implies that;

(n+2)=4 or  -(n+2)=4


This implies that;

n+2=4 or  n+2=-4


This simplifies to;

n=4-2 or  n=-4-2


n=2 or  n=--6


<u>SOLUTION TO QUESTION 7</u>

We have |2x-7|>1

This implies that;

2x-7>1 or -(2x-7)>1

We divide the second inequality by negative 1 and reverse the inequality sign.


2x-7>1 or 2x-7

We group like terms to get,


2x>1+7 or 2x


2x>8 or 2x

We divide both inequalities by 2 to obtain;


x>4 or x


<u>SOLUTION TO QUESTION 8</u>

Given A={1,2,3,4,5,6,7,8,9}

and

B={2.4,6,8}

The union of A and B, are the elements in set A or set B or both.

A \cup B={1,2,3,4,5,6,7,8,9}


<u>SOLUTION TO QUESTION 9</u>

Given:

P={1,5,7,9,13}

R={1,2,3,4,5,6,7}

and

Q={1,3,5}

We apply our understanding of subsets to draw the Venn diagram.

See attachment for the Venn Diagram.



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The value of x is 1.

* Let's explain how to solve the problem

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- Line QR intersects line PU at point R

- Line ST intersects line PU at point S

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- Look to the attached figure

∵ QR // ST

∴ m∠TSU = m∠QRU ⇒ corresponding angles

∵ m∠TSU = 15(x + 2)°

∴ m∠QRU = 15(x + 2)

∵ Points P, R, S lie on the same line

∵ RQ intersects PS at R

∵ m∠PRQ + m∠QRU = 180° ⇒ straight angle

∵ m∠PRQ = 135°

∵ m∠QRU = 15(x + 2)°

∴ 135 + 15(x + 2) = 180

∴ 135 + 15x + 30 = 180

- Add like terms

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∴ 15x = 15

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In geometry, parallel lines are coplanar instantly traces that do not intersect at any factor. Parallel planes are planes in identical three-dimensional space that in no way meet. Parallel curves are curves that do not touch every different or intersect and hold a set minimal distance

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For the function f(x)=ax^3+bx^2-5x+9, determine the values of a and b so that f(-1)=12 and f'(-1)=3
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If

<em>f(x)</em> = <em>ax</em> ³ + <em>bx</em> ² - 5<em>x</em> + 9

then

<em>f '(x)</em> = 3<em>ax </em>² + 2<em>bx</em> - 5

Given that <em>f</em> (-1) = 12 and <em>f</em> '(-1) = 3, we get the system of equations

-<em>a</em> + <em>b</em> + 5 + 9 = 12

3<em>a</em> - 2<em>b</em> - 5 = 3

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-<em>a</em> + <em>b</em> = -2

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Multiply through the first equation by 2 and add it to the second one to eliminate <em>b</em> and solve for <em>a</em> :

2(-<em>a</em> + <em>b</em>) + (3<em>a</em> - 2<em>b</em>) = 2(-2) + 8

-2<em>a</em> + 2<em>b</em> + 3<em>a</em> - 2<em>b</em> = -4 + 8

<em>a</em> = 4

Substitute this into the first equation above to solve for <em>b</em> :

-4 + <em>b</em> = -2

<em>b</em> = 2

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