Answer:
78 cm should be the correct answer
Step-by-step explanation:
Answer: Hello there!
this type of equations in one dimension (when all the factors are constants) are written as:
h = initial position + initial velocity*t + (acceleration/2)*t^2
First, let's describe the hunter's equation:
We know that Graham moves with a velocity of 1.5 ft/s, and when he is 18 ft above the ground, Hunter throws the ball, and because Graham is pulled with a cable, he is not affected by gravity.
If we define t= 0 when Graham is 18 ft above the ground, the equation for Graham height (in feet) is:
h = 18 + 1.5t
where t in seconds.
Now, the equation for the ball:
We know that at t= 0, the ball is thrown from an initial distance of 5ft, with an initial velocity of 24ft/s and is affected by gravity acceleration g, where g is equal to: 32.2 ft/s (notice that the gravity pulls the ball downwards, so it will have a negative sign)
the equation for the ball is:
h = 5 + 24t - (32.2/2)t^2 = 5 + 24t - 16.1t^2
So the system is:
h = 18 + 1.5t
h = 5 +24t - 16.1t^2
so the right answer is A
Answer:
C. These lines are perpendicular
Step-by-step explanation:
Answer:
Step-by-step explanation:
Givens
Length = a
Width = a + 3
Formulas
P = 2L + 2w
Area = L * w
Solution
Perimeter
P = 2L + 2w
P = 2*a + 2(a + 3) Remove the Brackets
p = 2a + 2a + 6 Combine
<u><em>P = 4a + 6</em></u>
Area
Area = L * w
Area = a (a + 3)
<u><em>Area = a^2 + 3a</em></u>
Answer:
1/125
Step-by-step explanation:
