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zaharov [31]
4 years ago
12

Please help with this

Mathematics
1 answer:
sergiy2304 [10]4 years ago
5 0

a. r + (-s) = r - s

b. r - (-s) = r + s

c. -r + (-s) = -r - s

d. -r - (-s) = -r + s

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Julie checked the prices of her five favorite CDs at Music Madness. What is the mode for these prices? $14, $12, $15, $12, $17
Shtirlitz [24]

$ 12

The mode is the value which occurs most often, in this case $ 12


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Describe the dimensions of two different prisms that each have a volume of 2400 cubic centimeters using work
kirza4 [7]

Answer:

Step-by-step explanation:

Alright, lets get started.

We have given the volume of a prism that is 2400 cubic centimeters.

we have not given which type of prism it is, so we are taking it as a rectangular prism.

The formula of volume of rectangular prism is :

Volume = l*w*h

Where l is length of base

w is width of base

h is height of prism

So,  2400=l*w*h

So, if we factor 2400 in two different manners, we could have two different dimensions of this prism having same volume that is 2400.

So, our first factor would be :

2400=20*20*6

Means the prism has base of 20 and 20 centimeters and height of 6 centimeters.

Our second factor would be :

2400=40*30*2

Means the prism has base of lenght 40 and width 30 and its height is 2 centimeters.

Hence we have two dimensions of prism, 20  20  6  and another one is 40  30  2.    :  Answer

Hope it will help :)


3 0
4 years ago
Which of the following number sentences is an example of the Distributive Property?
leonid [27]

Answer:

d. 7 × (10 + 9) = (7 × 10) + (7 × 9)

Step-by-step explanation:

The format of writing numbers in distributive property is a(b+c) = (a×b)+(a×c)

We can see that in choice d. 7 × (10 + 9) = (7 × 10) + (7 × 9) it is in correct format of writing numbers in distributive property. Thus, choice d. is correct.

Verification:-

a(b+c) = (a×b)+(a×c)

7 × (10 + 9) = (7 × 10) + (7 × 9)

7 0
3 years ago
Factor the polynomial function over the complex numbers. f(x)=x^3-2x^2+3x-6
Airida [17]

f(x)=x^3-2x^2+3x-6=x^2(x-2)+3(x-2)=(x-2)(x^2+3)\\\\i=\sqrt{-1}\to i^2=-1\\\\x^2+3=x^2-(-3)=x^2-3i^2=x^2-(\sqrt3)^2i^2)=x^2-(i\sqrt3)^2\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\\boxed{f(x)=(x-2)(x-i\sqrt3)(x+i\sqrt3)}

6 0
3 years ago
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