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3 years ago

9

Which is the best way to solve the equation ? square root of x = m?

2 answers:

skad [1K]3 years ago

6 0

M is two , is the answer

mr_godi [17]3 years ago

5 0

To solve the equation: sqrt(x) = m
Take the square of both sides to have (sqrt(x))^2 = m^2
=> x = m^2

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Leno4ka [110]

Answer:

$\frac{s^2-25}{(s^2+25)^2}$

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given: $\mathcal{L}[t \cos 5t]=(-1)F'(s)$ with $F(s)=\mathcal{L}[\cos 5t]$ .

Now, $F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt$ . Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that $F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt$ .

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

$F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s)$ .

Solving for F(s) on the last equation, $F(s)=\frac{s}{s^2+25}$ , then the Laplace transform we were searching is $-F'(s)=\frac{s^2-25}{(s^2+25)^2}$

3 0

2 years ago

Joan has a prescription for 100 capsules.She only have enough money to pay for 1/4 of her prescription.How many capsules will Jo

CaHeK987 [17]

Answer:25

Step-by-step explanation:

100 divided by 4 equals 25

8 0

3 years ago

Plzzz help plzzzzzzzzzzzzzz

mezya [45]

Given:

The figure of two quadrilaterals.

In $ABCD,AB=18,BC=20,CD=22,AD=24$

In $EFGH,EF=27,FG=30,GH=34, EH=36$

To find:

Whether the figures are congruent, similar or neither.

Solution:

Ratio of corresponding sides are:

$\dfrac{AB}{EF}=\dfrac{18}{27}$

$\dfrac{AB}{EF}=\dfrac{2}{3}$

Similarly,

$\dfrac{BC}{FG}=\dfrac{20}{30}$

$\dfrac{BC}{FG}=\dfrac{2}{3}$

$\dfrac{CD}{GH}=\dfrac{22}{34}$

$\dfrac{CD}{GH}=\dfrac{11}{17}$

And,

$\dfrac{AD}{EH}=\dfrac{24}{36}$

$\dfrac{AD}{EH}=\dfrac{2}{3}$

Clearly, $\dfrac{AB}{EF}=\dfrac{BC}{FG}=\dfrac{AD}{EH}\neq \dfrac{CD}{GH}$ .

All corresponding sides are not proportional.

Therefore, the figures are neither similar nor congruent. Hence, third option is correct.

7 0

2 years ago

Compare 7/12 and 1/2

Klio2033 [76]

7/12 and 1/2
Get the common denominator
Multiply 1/2 by 6
7/12 and 6/12

3 0

3 years ago

Read 2 more answers

HELP!! T.T This is due tonight!!!

lesya [120]

D and e would be the answer

3 0

2 years ago