All categories

2 years ago

X/8 =.42 solve for X

Mathematics

1 answer:

uysha [10]2 years ago

7 0

Answer:

x = 3.36

Step-by-step explanation:

$\frac{x}{8} = \frac{.42}{1}$ , if we have a fraction = fraction then we can cross multiply to have a multiplication problem

x · 1 = 8 · 0.42, multiply

x = 3.36

You might be interested in

Which function grows at the fastest rate for increasing values of x?

Andreyy89

Take derivitive of each

f'(x)=9
g'(x)=4
h'(x)=12x

so duh, when x>0.75 then h(x) grows at fastest rate, after that. it just keeps going up

7 0

3 years ago

Read 2 more answers

If the measure of each exterior angle of a regular polygon is 18°, determine how many sides the polygon has.

Sveta_85 [38]

we are given

exterior angle is 18

so,

$\theta=18$

now, we can use formula

number of sides of regular polygon = 360/(exterior angle)

so, we get

$n=\frac{360}{18}$

$n=20$

so, number sides is 20..........Answer

7 0

2 years ago

1. You are choosing a movie from your friend’s movie collection. You can choose 1 of 4 comedies, 1 of 5 dramas, or 1 of 3 classi

lakkis [162]

3 different ways for choosing a movie

3 0

2 years ago

Which triangle has a bigger area: 1. A triangle with sides measuring 300, 400, and 500. 2. A triangle with sides measuring 300,

Kitty [74]

A triangle with sides measuring 300, 400 and 700 because 300+400+700=1400 which is higher than the first triangle 300+400+500=1200

6 0

3 years ago

Find the exact value of sin2 theta given sin theta =5/13, 90°<theta <180°

Zepler [3.9K]

Now, we know that 90°< θ <180°, that simply means the angle θ is in the II quadrant, where sine is positive and cosine is negative.

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{13}}\impliedby \textit{now let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}$

$\bf \pm\sqrt{13^2-5^2}=a\implies \pm\sqrt{144}=a\implies \pm 12 =a \implies \stackrel{II~quadrant}{-12=a}
\\\\\\
therefore \qquad cos(\theta )=\cfrac{\stackrel{adjacent}{-12}}{\stackrel{hypotenuse}{13}}
\\\\
-------------------------------\\\\
sin(2\theta )\implies 2sin(\theta )cos(\theta )\implies 2\left(\frac{5}{13} \right)\left( \frac{-12}{13} \right)\implies -\cfrac{120}{169}$

3 0

3 years ago