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2 years ago

Four sizes of scaled text are shown.

Mathematics

1 answer:

stich3 [128]2 years ago

8 0

Answer:

0.880

Step-by-step explanation:

A thousandth is a thousand part of a number.

The extreme 8 is the hundredth in 0.878, rounding off gives 0.880

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If we wish to obtain a 95% confidence interval of a parameter using the bootstrap method, we determine the _______ percentile

BigorU [14]

Answer:

2.5th percentile and the 97.5th percentile.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

So we obtain the 0.025*100 = 2.5th percentile and the (1-0.025)*100 = 97.5th percentile.

So the answer is:

2.5th percentile and the 97.5th percentile.

8 0

2 years ago

Find an equation of the tangent plane to the given parametric surface at the specified point.

Neko [114]

Answer:

Equation of tangent plane to given parametric equation is:

$\frac{\sqrt{3}}{2}x-\frac{1}{2}y+z=\frac{\pi}{3}$

Step-by-step explanation:

Given equation

$r(u, v)=u cos (v)\hat{i}+u sin (v)\hat{j}+v\hat{k}$ ---(1)

Normal vector tangent to plane is:

$\hat{n} = \hat{r_{u}} \times \hat{r_{v}}\\r_{u}=\frac{\partial r}{\partial u}\\r_{v}=\frac{\partial r}{\partial v}$

$\frac{\partial r}{\partial u} =cos(v)\hat{i}+sin(v)\hat{j}\\\frac{\partial r}{\partial v}=-usin(v)\hat{i}+u cos(v)\hat{j}+\hat{k}$

Normal vector tangent to plane is given by:

$r_{u} \times r_{v} =det\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\cos(v)&sin(v)&0\\-usin(v)&ucos(v)&1\end{array}\right]$

Expanding with first row

$\hat{n} = \hat{i} \begin{vmatrix} sin(v)&0\\ucos(v) &1\end{vmatrix}- \hat{j} \begin{vmatrix} cos(v)&0\\-usin(v) &1\end{vmatrix}+\hat{k} \begin{vmatrix} cos(v)&sin(v)\\-usin(v) &ucos(v)\end{vmatrix}\\\hat{n}=sin(v)\hat{i}-cos(v)\hat{j}+u(cos^{2}v+sin^{2}v)\hat{k}\\\hat{n}=sin(v)\hat{i}-cos(v)\hat{j}+u\hat{k}\\$

at u=5, v =π/3

$=\frac{\sqrt{3} }{2}\hat{i}-\frac{1}{2}\hat{j}+\hat{k}$ ---(2)

at u=5, v =π/3 (1) becomes,

$r(5, \frac{\pi}{3})=5 cos (\frac{\pi}{3})\hat{i}+5sin (\frac{\pi}{3})\hat{j}+\frac{\pi}{3}\hat{k}$

$r(5, \frac{\pi}{3})=5(\frac{1}{2})\hat{i}+5 (\frac{\sqrt{3}}{2})\hat{j}+\frac{\pi}{3}\hat{k}$

$r(5, \frac{\pi}{3})=\frac{5}{2}\hat{i}+(\frac{5\sqrt{3}}{2})\hat{j}+\frac{\pi}{3}\hat{k}$

From above eq coordinates of r₀ can be found as:

$r_{o}=(\frac{5}{2},\frac{5\sqrt{3}}{2},\frac{\pi}{3})$

From (2) coordinates of normal vector can be found as

$n=(\frac{\sqrt{3} }{2},-\frac{1}{2},1)$

Equation of tangent line can be found as:

$(\hat{r}-\hat{r_{o}}).\hat{n}=0\\((x-\frac{5}{2})\hat{i}+(y-\frac{5\sqrt{3}}{2})\hat{j}+(z-\frac{\pi}{3})\hat{k})(\frac{\sqrt{3} }{2}\hat{i}-\frac{1}{2}\hat{j}+\hat{k})=0\\\frac{\sqrt{3}}{2}x-\frac{5\sqrt{3}}{4}-\frac{1}{2}y+\frac{5\sqrt{3}}{4}+z-\frac{\pi}{3}=0\\\frac{\sqrt{3}}{2}x-\frac{1}{2}y+z=\frac{\pi}{3}$

5 0

2 years ago

What is the slope of the graph of 12x + 3y = –17?

garik1379 [7]

To get the slope you need to solve for y:
12x+3y=-17
Subtract 12x from both sides:
3y=-12x-17
Divide everything by 3:
y=-4x-17/3
The slope is -4.

3 0

3 years ago

A right rectangular prism is made with 8 small cubes.

sineoko [7]

Answer:

C. ⁸/125

Step-by-step explanation:

The volume of the right rectangular prism = 8 × volume of 1 cube

Volume of cube = a³

Where,

a = ⅕ inch

Volume of 1 cube = (⅕)³

= 1/125 cubic inch

✔️Volume of the rectangular prism = 8 × ¹/125

= ⁸/125 cubic inch

8 0

3 years ago

Mr. Ellis owns a landscaping company. He sends two crews to mow grass. Crew A mows 6 acres in 7.5 hours. Crew B mows 4.5 acres i

In-s [12.5K]

Hey there!

The answer to your question is Crew A

We can find this by first finding the unit rate, or acres per hour. We can divide the amount of acres by the amount of hours.

Crew A : 6/7.5 = 0.8 acres per hour

Crew B : 4.5/6 = 0.75 acres per hour

With the data above, we can see that Crew A is faster.

Hope it helps and have an amazing day! Remember, You've got this!

5 0

2 years ago

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