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8090 [49]
3 years ago
7

An auto transport truck holds 12 cars. A car dealer plans to bring in 1,006 new cars in June and July. If an auto transport truc

k is filled for each delivery, except for the last one, how many full truckloads are needed and how many cars will be in the last truck?

Mathematics
1 answer:
marin [14]3 years ago
3 0
To find the number of full trucks we can do 1006 / 12. This gives us 83.8333. That is, 83 full trucks and a bit left over.
The bit left over is the answer to the second part, the last truck. 0.8333 is the same as 10/12, so the last truck will have 10 cars in it. If we didn’t know that fraction, we could find the answer by saying 12x83 = 996. 1006 - 996 = 10.

So the final answer is: 83 full trucks and 10 cars in the last truck.
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Answer:  The area of the parallelogram is:
_______________________________________________________
\frac{9393}{8}  in² = 1174 ⅛  in² = 1174.125 in² .
_______________________________________________________
Explanation:
_______________________________________________________
Area of a parallelogram:
_______________________________________________________
 A = base * height = b * h ;

From the figure (from the actual "question"):
_______________________________________
         b = 50.5 in.

         h = 23.25 in.
____________________________________________________________
Method 1)  A = b * h =
                 
                     =  (50.5 in) * (23.25 in) = 1174.125 in² ; or, write as:  1174 <span>⅛ .
</span>____________________________________________________________
Method 2)  A = b * h =
             
                      =  (50 ½ in) * (23 <span>¼ in) =
   
                      =    (</span>\frac{101}{2} in) * (\frac{93}{4}<span> in) ;
</span>___________________________________________________________
Note:  "50 ½ " = [(50*2) + 1 ] / 2  = \frac{101}{2} ;

Note:  "23 ¼ " = [(23*4) + 1 ] / 4  = \frac{93}{4} ;
____________________________________________________________
→  A =  (\frac{101}{2} in) * (\frac{93}{4} in) ;
 
→  A = \frac{(101*93)}{(2*4)}  in² = \frac{9393}{8}  in² ; 
          
→  A = (9393/8) in² =  
         
→  A  = \frac{9393}{8}  in² = 1174 ⅛  in² = 1174.125 in² .
________________________________________________________
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