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8090 [49]
2 years ago
7

An auto transport truck holds 12 cars. A car dealer plans to bring in 1,006 new cars in June and July. If an auto transport truc

k is filled for each delivery, except for the last one, how many full truckloads are needed and how many cars will be in the last truck?

Mathematics
1 answer:
marin [14]2 years ago
3 0
To find the number of full trucks we can do 1006 / 12. This gives us 83.8333. That is, 83 full trucks and a bit left over.
The bit left over is the answer to the second part, the last truck. 0.8333 is the same as 10/12, so the last truck will have 10 cars in it. If we didn’t know that fraction, we could find the answer by saying 12x83 = 996. 1006 - 996 = 10.

So the final answer is: 83 full trucks and 10 cars in the last truck.
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A city has a population of 230,000 people. Suppose that each year the population grows by 8.5%. What will the population be afte
worty [1.4K]

Answer:

720,682.92

Step-by-step explanation:

8.5% = 0.085

P(t) = Initial Population * (1 + rate)t

P(t) = 230,000(1 + 0.085)t

P(t) = 230,000(1.085)t

P(14) = 230,000(1.085)14

P(14) = 720,682.82

6 0
2 years ago
Work the following problem
neonofarm [45]

Answer:

Option B is the correct answer.

Step-by-step explanation:

Given

List Price=$720

The percentage of discount=13%

In order to find the amount of discount, 13% of the amount has to be calculated. To calculate 13% , the amount is multiplied by 13/100.

Amount of discount=13% of list price

=720*13/100

=720*0.13

=$93.60

The amount of discount is $93.6..

5 0
3 years ago
A manufacturer produces light bulbs that have a mean life of at least 500 hours when the production process is working properly.
denpristay [2]

Answer:

We conclude that the population mean light bulb life is at least 500 hours at the significance level of 0.01.

Step-by-step explanation:

We are given that a manufacturer produces light bulbs that have a mean life of at least 500 hours when the production process is working properly. The population standard deviation is 50 hours and the light bulb life is normally distributed.

You select a sample of 100 light bulbs and find mean bulb life is 490 hours.

Let \mu = <u><em>population mean light bulb life.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 500 hours      {means that the population mean light bulb life is at least 500 hours}

Alternate Hypothesis, H_A : \mu < 500 hours     {means that the population mean light bulb life is below 500 hours}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                           T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean bulb life = 490 hours

           σ = population standard deviation = 50 hours

           n = sample of light bulbs = 100

So, <u><em>the test statistics</em></u>  =  \frac{490-500}{\frac{50}{\sqrt{100} } }

                                     =  -2

The value of z test statistics is -2.

<u>Now, at 0.01 significance level the z table gives critical value of -2.33 for left-tailed test.</u>

Since our test statistic is higher than the critical value of z as -2 > -2.33, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis.</u>

Therefore, we conclude that the population mean light bulb life is at least 500 hours.

7 0
3 years ago
Can someone help me with this??<br><br> thanks
viva [34]
Number of tickets: T.
Number of customers: c 
Initially the number of tickets is T0=150, when the group hasn't sold any tickets (c=0). Then the graph must begin with c=0 and T=150. Point=(0,150). Possible options: Graph above to the right and graph below to the left.
They sell the tickets in pack of three tickets per customer c, then each time they sell a pack of three tickets to a customer, the number of tickets is reduced by 3 (-3c). Then the number of tickets, T, the group has left after selling tickets to c customers is:
T=150-3c→T=-3c+150

For T=0→-3c+150=0→150=3c→150/3=c→c=50. The graph must finish with c=50, T=0. Final point=(c,T)=(50,0)

Answer:
The correct graph is above to the right, beginning on vertical axis with T=150 and finishing on horizontal axis with c=50.
The correct equation is T=-3c+150

7 0
2 years ago
Read 2 more answers
This is rlly hard i need help both pls
mart [117]

Answer:

length times hight times whith

4 0
3 years ago
Read 2 more answers
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